Solving Quadratic Equations By Completing The Square

The Organic Chemistry Tutor
19 Jan 201807:57
EducationalLearning
32 Likes 10 Comments

TLDRThis lesson teaches how to solve quadratic equations by completing the square. It walks through three examples, starting with a simple equation x^2 + 4x = 5, leading to solutions x = 1 and x = -5. The second example involves factoring and rationalizing to find x = 3 ± 5√2/2. The third example demonstrates solving a more complex equation, resulting in x = 5/6 ± √145/6. Each step is clearly explained, ensuring a comprehensive understanding of the method.

Takeaways
  • πŸ“š The lesson is about solving quadratic equations by completing the square.
  • πŸ” To complete the square, take half of the coefficient of 'x', square it, and add it to both sides of the equation.
  • βš–οΈ Ensure balance by performing the same operation on both sides of the equation.
  • πŸ“ Factor the quadratic expression after adding the square term to get a product of binomials.
  • πŸ”’ Apply the square root to both sides to solve for 'x', resulting in two potential solutions.
  • πŸ“Œ For the equation \( x^2 + 4x = 5 \), the solutions are \( x = 1 \) and \( x = -5 \).
  • πŸ“‰ Demonstrated solving a quadratic equation by completing the square with a leading coefficient other than 1.
  • πŸ“ Factored out the leading coefficient and completed the square for the equation \( 2x^2 - 12x - 7 = 0 \).
  • πŸ“ˆ Found the solutions for the second example to be \( x = 3 + \frac{5\sqrt{2}}{2} \) and \( x = 3 - \frac{5\sqrt{2}}{2} \).
  • πŸ“˜ Showed the process of solving a quadratic equation with a non-integer coefficient by completing the square.
  • πŸ“™ The third example equation \( 3x^2 - 5x = 10 \) was solved, resulting in \( x = \frac{5}{6} \pm \frac{\sqrt{145}}{6} \).
Q & A
  • What is the method used in the script to solve quadratic equations?

    -The script uses the method of completing the square to solve quadratic equations.

  • What is the first step in completing the square for the equation x squared plus 4x equals 5?

    -The first step is to take half of the coefficient of x, which is 2 (half of 4), and square it to get 4, then add this to both sides of the equation.

  • How is the expression x squared plus 4x plus 4 factored in the script?

    -The expression is factored as (x + 2)(x + 2), which is the product of (x + the number that was squared).

  • What are the solutions for x in the first example after completing the square and taking the square root of both sides?

    -The solutions for x are x = 1 and x = -5, obtained by subtracting 2 from both sides of the equations x + 2 = 3 and x + 2 = -3, respectively.

  • How does the script handle the second example with the equation 2x squared minus 12x minus 7 equals zero?

    -The script first moves the constant term to the other side, factors out the 2, completes the square by adding 18 to both sides, and then solves for x by taking the square root of both sides.

  • What is the process to rationalize the denominator in the second example's solution?

    -The process involves multiplying the numerator and denominator by the square root of 2 to eliminate the square root in the denominator.

  • What is the final simplified form of the solutions for the second example in the script?

    -The final simplified form of the solutions is x = 3 plus or minus 5 root 2 over 2.

  • How does the script approach the third example with the equation three x squared minus five x equals ten?

    -The script factors out a 3 from the first two terms, completes the square by adding 25/36 to both sides, and then solves for x by taking the square root of both sides.

  • What is the common mistake to avoid when completing the square, as implied in the script?

    -The common mistake to avoid is not squaring the entire term that is added to both sides of the equation.

  • Why is it necessary to multiply both sides by 1/3 in the third example in the script?

    -It is necessary to eliminate the coefficient of x squared (which is 3) by multiplying both sides by 1/3, simplifying the equation to a form where the square root can be taken.

  • What are the final solutions for x in the third example after completing the square and simplifying?

    -The final solutions for x are x = 5/6 plus or minus root 145/6.

Outlines
00:00
πŸ“š Solving Quadratic Equations by Completing the Square

This paragraph introduces the method of solving quadratic equations by completing the square. The example given is \( x^2 + 4x = 5 \). The process involves taking half of the coefficient of x, squaring it, and adding it to both sides of the equation. The equation is then factored into \( (x + 2)^2 = 9 \), and the square root is taken to find two solutions: \( x = 1 \) and \( x = -5 \). The paragraph also includes a second example, \( 2x^2 - 12x - 7 = 0 \), which is solved similarly by factoring out the 2, completing the square, and finding the solutions \( x = 3 + \frac{5\sqrt{2}}{2} \) and \( x = 3 - \frac{5\sqrt{2}}{2} \).

05:03
πŸ” Completing the Square for Complex Quadratics

The second paragraph continues the theme of completing the square but with a more complex example, \( 3x^2 - 5x = 10 \). The solution starts by factoring out a 3, then taking half of the new coefficient of x and squaring it to complete the square. The equation is transformed into \( \frac{(x - \frac{5}{6})^2}{3} = \frac{145}{12} \). The square root of both sides is taken, leading to the final solutions \( x = \frac{5}{6} + \frac{\sqrt{145}}{6} \) and \( x = \frac{5}{6} - \frac{\sqrt{145}}{6} \). The paragraph also discusses the challenges of simplifying the square root of 145 and presents the final answer as a single fraction with a common denominator.

Mindmap
Keywords
πŸ’‘Quadratic Equations
Quadratic equations are polynomial equations of degree two, typically in the form of ax^2 + bx + c = 0, where a, b, and c are constants. In the video, the theme revolves around solving such equations using a specific method called 'completing the square.' The script provides step-by-step solutions to various quadratic equations, demonstrating the application of this method.
πŸ’‘Completing the Square
Completing the square is a technique used to solve quadratic equations by transforming them into a perfect square trinomial plus a constant. It involves taking half the coefficient of the linear term (x), squaring it, and adding this value to both sides of the equation. The script illustrates this process with multiple examples, showing how it simplifies the solving process.
πŸ’‘Factoring
Factoring is the process of breaking down a polynomial into a product of its factors. In the context of completing the square, after adding the square term, the quadratic expression is factored into the form (x + p)^2. The script shows factoring as a step following the completion of the square, which helps in solving for x.
πŸ’‘Square Root
The square root operation is used to find a value that, when multiplied by itself, gives the original number. In the script, taking the square root is a step applied after completing the square to solve for x, resulting in ±√(value), which leads to two potential solutions for x.
πŸ’‘Coefficient
A coefficient is a numerical factor in a term of a polynomial. In the script, coefficients are essential in determining the steps for completing the square, as they dictate the values that are halved and squared to form the perfect square trinomial.
πŸ’‘Linear Term
The linear term in a quadratic equation is the term with the variable raised to the first power, represented as bx in the standard form. The script explains that half of the coefficient of the linear term is used to complete the square.
πŸ’‘Perfect Square Trinomial
A perfect square trinomial is a special form of a quadratic expression that can be factored into the square of a binomial. The script demonstrates how to create a perfect square trinomial by adding a specific value to both sides of the equation, which is derived from the square of half the coefficient of the linear term.
πŸ’‘Rationalizing the Denominator
Rationalizing the denominator is the process of eliminating the radicals (square roots) from the denominator of a fraction. In the script, this is done by multiplying the numerator and denominator by the square root of the denominator's radical part, as shown in the example where the denominator is √2.
πŸ’‘Common Denominator
A common denominator is a denominator that is the same for two or more fractions, allowing them to be added or subtracted. The script mentions finding a common denominator when combining fractions after completing the square, which is necessary for simplifying the equation further.
πŸ’‘Solving for Variable
Solving for a variable involves finding the value(s) of the variable that make the equation true. In the context of the script, solving for the variable x involves various steps, including completing the square, factoring, and applying the square root, which ultimately yields the value(s) of x.
Highlights

Introduction to solving quadratic equations by completing the square.

Demonstration of completing the square for the equation x^2 + 4x = 5.

Explanation of adding 2^2 to both sides of the equation to balance it.

Factoring the quadratic expression x^2 + 4x + 4 into (x + 2)(x + 2).

Calculating the right side of the equation as 5 + 4 = 9.

Solving for x by taking the square root of both sides, resulting in x + 2 = Β±3.

Finding the solutions x = 1 and x = -5 by isolating x.

Starting the second example with the equation 2x^2 - 12x - 7 = 0.

Factoring out a 2 from the equation and completing the square for x^2 - 6x.

Adding 18 to both sides to balance the equation after completing the square.

Factoring the new quadratic expression x^2 - 6x + 9 into (x - 3)(x - 3).

Solving the equation by taking the square root of both sides, resulting in x - 3 = ±√(25/2).

Rationalizing the denominator and finding the solutions x = 3 ± (5√2)/2.

Starting the third example with the equation 3x^2 - 5x = 10.

Factoring out a 3 and completing the square for x^2 - (5/3)x.

Adding (5/6)^2 * 3 to both sides to balance the equation.

Factoring the new quadratic expression and finding the right side of the equation.

Solving for x by taking the square root of both sides and simplifying the equation.

Final solutions for x expressed as x = 5/6 ± √145/6.

Transcripts
Rate This

5.0 / 5 (0 votes)

Thanks for rating: