Physics - Ch 66 Ch 4 Quantum Mechanics: Schrodinger Eqn (65 of 92) Wave Constants B=? C=?
TLDRIn this online lecture, the presenter discusses the quantum mechanical behavior of particles encountering a potential barrier. Despite the particle's energy exceeding the barrier's energy, a phenomenon occurs where some particles are transmitted and others are reflected, contrary to classical mechanics. The lecture focuses on deriving two key equations that describe the wave function on either side of the barrier and uses boundary conditions to solve for the constants, ultimately aiming to calculate the transmission (T) and reflection (R) probabilities of the particles.
Takeaways
- π In quantum mechanics, particles can be both transmitted and reflected even when their energy exceeds the potential barrier.
- π The wave function is described by two equations on either side of the boundary, with different conditions on the left (no potential barrier) and right (with potential barrier).
- π’ The potential barrier in the example is smaller than the particle's energy, leading to partial reflection and transmission of particles.
- π― At the boundary (x=0), the wave function must satisfy two conditions: the function itself and its derivative must be continuous.
- π§ By setting x=0, we derive the first equation relating the coefficients A, B, and C of the wave function.
- π The second equation is obtained by taking the derivative of the wave functions and ensuring the slopes are continuous at the boundary.
- π By solving these equations, we can express the coefficients B and C in terms of the coefficient A.
- π The process of solving for B and C allows us to eliminate these coefficients, leaving us with a single constant A in the wave functions.
- π’ The wave numbers (k1 and k2) are crucial in defining the equations and are related to the particle's energy on each side of the boundary.
- π The final equations will enable us to calculate the transmission (T) and reflection (R) probabilities of the particles in future videos.
- π The script provides a foundation for understanding quantum behavior at potential barriers and sets the stage for further analysis of particle transmission and reflection.
Q & A
What is the main topic of the lecture?
-The main topic of the lecture is the behavior of wave functions in quantum mechanics, specifically when particles encounter a potential barrier.
What is the significance of the potential barrier being smaller than the particle's energy?
-When the potential barrier is smaller than the particle's energy, part of the particles will be transmitted and part will be reflected, which is a phenomenon not observed in classical mechanics.
What are the two key equations derived in the lecture?
-The two key equations derived in the lecture describe the wave function on both sides of the boundary where a potential barrier exists.
Why is it important to find the values of B and C in terms of A?
-Finding the values of B and C in terms of A is important because it allows us to solve for the wave functions with only one constant, which is necessary for determining the transmission (T) and reflection (R) probabilities of the particles.
What does the continuity condition at the boundary imply?
-The continuity condition at the boundary implies that the slope of the function on the left side of the boundary must equal the slope of the function on the right side, ensuring a smooth transition of the wave function across the boundary.
How are the wave numbers (k1 and k2) related to the energies of the particles?
-The wave numbers (k1 and k2) are defined by the energies of the particles on the respective sides of the boundary, according to the laws of quantum mechanics.
What happens at the boundary when x equals zero?
-When x equals zero, we use the derived equations to find the relationship between the coefficients A, B, and C of the wave functions, which helps in understanding the transmission and reflection of particles.
What is the significance of the equation K1*B + K2*B = K1*A - K2*A?
-This equation is used to solve for B in terms of A, which is a crucial step in eliminating B and finding the transmission and reflection coefficients.
How does the cancellation of K2 in the numerator and denominator simplify the equation for C?
-The cancellation of K2 in the numerator and denominator simplifies the equation for C, allowing us to express C in terms of A more clearly, which is necessary for further calculations.
What will be covered in the future videos?
-In future videos, the lecture series will show how to use the derived equations and constants to calculate the transmission (T) and reflection (R) probabilities of particles at the boundary.
Why is it assumed that D is equal to zero?
-It is assumed that D is equal to zero because once the particles pass the initial part of the barrier and enter region two, none of them will return, meaning there are no particles moving to the left past the boundary.
Outlines
π Quantum Mechanics: Wave Function and Barrier
This paragraph introduces the concept of wave functions in quantum mechanics, focusing on the behavior of particles encountering a potential barrier. It explains that despite the particle's energy being greater than the barrier's energy, a portion of the particles will be reflected, which is a phenomenon not observed in classical mechanics. The speaker presents two equations that describe the wave function on both sides of the boundary and emphasizes the importance of understanding what happens at the boundary where x equals zero. The equations lead to the conclusion that the coefficients A, B, C, and D must satisfy certain conditions for continuity and slope at the boundary. The goal is to solve for B and C in terms of A to simplify the equations and ultimately determine the transmission (T) and reflection (R) probabilities of the particles.
π Solving for Coefficients in Quantum Barrier Scenario
The second paragraph delves into the process of solving for the coefficients B and C in terms of A, which is necessary for understanding particle transmission and reflection probabilities. The speaker guides through the algebraic manipulation of the equations, aiming to isolate B and C. By replacing B with its equivalent expression and solving the resulting equations, the speaker derives a formula for B in terms of A. Similarly, the process is repeated to express C in terms of A. The paragraph concludes with the achievement of two key equations that express B and C solely in terms of A, setting the stage for future calculations of transmission and reflection probabilities, which will be covered in subsequent videos.
Mindmap
Keywords
π‘Wave Function
π‘Potential Barrier
π‘Quantum Mechanics
π‘Particle Energy
π‘Boundary
π‘Reflection
π‘Transmission
π‘Constants
π‘Derivative
π‘Transmission Coefficient (T)
π‘Reflection Coefficient (R)
Highlights
The lecture discusses the behavior of particles in quantum mechanics versus classical mechanics when encountering a potential barrier.
In quantum mechanics, even when the particle's energy exceeds the barrier's energy, some particles are reflected and some are transmitted.
The potential barrier in the example is smaller than the particle's energy, leading to both reflection and transmission of particles.
Two equations are derived to describe the wave function on both sides of the boundary, one without a potential barrier and one with.
At the boundary, the wave function must satisfy two conditions: the function itself and its derivative must be continuous.
The continuity of the wave function at the boundary leads to the first equation: A + B must equal C, with the understanding that D is already zero.
The second condition for the wave function at the boundary is that the slope on the left must equal the slope on the right, leading to the equation k1*A - k1*B = k2*C.
By setting X equal to zero and taking the derivative of both functions, the equation k1*A - k1*B = k2*C is derived.
The equations are used to solve for B and C in terms of A, which simplifies the process of finding the transmission (T) and reflection (R) probabilities.
The equation B = A*(k1 - k2) / (k1 + k2) is derived to express B in terms of A, which is a key step in the analysis.
Similarly, the equation C = A*(2*k1) / (k1 + k2) is derived, which allows C to be expressed in terms of A.
With B and C expressed in terms of A, the wave functions on both sides of the boundary are now described using a single constant, A.
These derived expressions for B and C will be used in future videos to calculate the transmission and reflection probabilities.
The wave numbers k1 and k2 are associated with the energy of the particle on either side of the boundary and are crucial in the equations.
The lecture provides a detailed mathematical framework for understanding quantum tunneling and the behavior of particles at potential barriers.
The process of deriving the equations and solving for B and C demonstrates the application of boundary conditions in quantum mechanics.
The lecture is part of a series that will eventually show how to calculate the transmission and reflection probabilities, which have practical applications in understanding quantum phenomena.
Transcripts
Browse More Related Video
Physics - Ch 66 Ch 4 Quantum Mechanics: Schrodinger Eqn (64 of 92) Transmission-Reflection (Q.M.)
Physics - Ch 66 Ch 4 Quantum Mechanics: Schrodinger Eqn (62 of 92) Transmission vs Reflection
Physics - Ch 66 Ch 4 Quantum Mechanics: Schrodinger Eqn (77 of 92) The Barrier: An Overview
Physics - Ch 66 Ch 4 Quantum Mechanics: Schrodinger Eqn (74 of 92) R=? T=? V0=(3/4)E,.(Ex. 4 of 4)
Physics - Ch 66 Ch 4 Quantum Mechanics: Schrodinger Eqn (73 of 92) R=? T=? V0=(1/2)E (Ex. 3 of 4)
Physics - Ch 66 Ch 4 Quantum Mechanics: Schrodinger Eqn (76 of 92) Penetration Depth V0, E: Ex.
5.0 / 5 (0 votes)
Thanks for rating: