Evaluating Surface Integrals
TLDRSurface integrals generalize line integrals to two-dimensional surfaces. The script introduces the notation for surface integrals, parameterizing the surface S with variables u and v. The differential element dS represents an infinitesimal area patch of the surface. When S is the graph of a function z=f(x,y), we can use x and y as parameters, and dS has a simplified form requiring only partial derivatives of z. With vector fields, the flux (flow through the surface per unit area) is expressed as an integral of the normal component over S; normal vectors point orthogonally outward. Surface integrals arise naturally in physics and many applications.
Takeaways
- π Surface integrals generalize line integrals to integration over a surface S instead of a curve C.
- π To set up a surface integral, the surface S is parameterized by variables u and v as a vector r.
- π€ The key element is the expression for dS, which involves a cross product of r's partial derivatives.
- π For a surface z=g(x,y), x and y serve as parameters and dS simplifies to a square root expression.
- π§ The integral of 1 over a surface gives its surface area over the domain.
- π€ Surface integrals also work for vector fields F, giving the flux of F across the surface.
- π€ The normal vector n points perpendicularly out from the surface at each point.
- π³ For parameterized surfaces, n = (ru x rv) / |ru x rv| and can be used directly.
- π For z=g(x,y) surfaces, n simplifies and flux has an easy double integral expression.
- π‘ Surface integrals have applications like Gauss's Law relating charge and electric flux.
Q & A
What are surface integrals and how are they related to line integrals?
-Surface integrals integrate a function over a surface in 3D space, much like line integrals integrate functions over a curve in 2D space. So surface integrals are a higher dimensional generalization of line integrals.
Why do we parameterize the surface S when setting up a surface integral?
-Parameterizing the surface S in terms of variables u and v allows us to express dS and the surface integral in calculable terms using the parameterization.
What is the interpretation of evaluating a surface integral over a surface S with f(x,y,z)=1?
-When f(x,y,z)=1, the surface integral gives the surface area of S across the domain of integration.
How do we calculate the normal vector n for a given surface S?
-The normal vector n at each point of surface S are unit vectors perpendicular to the surface pointing outward. We can visualize running a tangent plane across S - n points in the direction sticking straight out of this plane.
What is the flux of a vector field F across a surface S?
-The flux describes the total amount of F passing through S. We can calculate it as the surface integral of F dot n over S, where n is the normal vector.
What is a simplified case for setting up surface integrals?
-If the surface z=g(x,y) is just a function of x and y, we can use x and y as parameter variables. This simplifies the surface integral setup.
How do we find dS for the simplified case z=g(x,y)?
-dS = sqrt[(dz/dx)^2 + (dz/dy)^2 + 1] dx dy for z=g(x,y). We just need the partial derivatives of z.
How can we express surface integrals with vector fields?
-F Β· (ru x rv) dS integrates the flux of a vector field F through a parameterized surface with r(u,v). For z=g(x,y) it is β«β« (-P dz/dx - Q dz/dy + R) dx dy.
What are some applications of surface integrals?
-Surface integrals have applications in physics, like in Gauss's Law relating electric flux through a closed surface to enclosed charge. They also appear in integral theorems.
What is the evaluated flux in the full example problem?
-In the example with F(x,y,z) = <x^2, xy, z> and surface z=x+y^2 from x=0 to 1, y=0 to 1, the flux evaluates to 1/6.
Outlines
π Defining and Setting Up Surface Integrals
Introduces surface integrals conceptually as a higher dimensional analog of line integrals, requiring a surface S to integrate over instead of a curve C. Explains parameterizing the surface S using u and v, with coordinate vector r, and shows the surface integral expression using cross product of partial derivatives ru and rv. Gives an example parameterizing a surface and walking through the setup.
π Simplified Case for z=f(x,y) Surfaces
Discusses a common simplified case where the surface z coordinates are given as a function of x and y only. Shows a simplified dS derivation and surface integral expression using partial derivatives of z instead of a full parameterization.
π’ Vector Field Surface Integrals and Flux
Extends surface integrals to vector fields using the normal vector n, calculating total flux through the surface. Derives the integral expression with n, ru, and rv. Revisits the z=f(x,y) case for simpler flux calculations. Gives a complete example evaluating the flux for a sample surface and vector field.
Mindmap
Keywords
π‘surface integral
π‘parameterization
π‘normal vector
π‘flux
π‘Gauss's law
π‘differential area
π‘double integral
π‘tangent plane
π‘bounds
π‘line integral
Highlights
Surface integrals can be thought of as a higher dimensional equivalent to line integrals
The complexity comes from constraining to the surface S, just like constraining line integrals to the path of a curve
The surface S is parameterized in terms of two new variables u and v to express dS in terms we can use
The interpretation of surface integrals is more abstract, but with f=1 it gives back the surface area of S
There is a simplified case for surfaces that are only a function of x and y, where x and y serve as parametric variables
Surface integrals can also be used with vector fields to calculate the "flux" or amount of the field passing through the surface
The normal vector n points perpendicular out from the surface, visualizing a flat paper tangent plane
For general parameterized surfaces, flux is the double integral of F dot (ru x rv)
For surfaces given by z=f(x,y), flux is the double integral of (-P dz/dx - Q dz/dy + R)
Example calculating flux of a vector field through a surface z=x+y^2
Surface integrals relate total charge to electric flux in Gauss's Law
Surface integrals are used in theorems relating volume and surface area
Setting up surface integrals involves parameterizing the surface S in terms of new variables u and v
The magnitude of the cross product of partial derivatives gives an element of surface area dS
The normal vector n is key for calculating flux of vector fields across surfaces
Transcripts
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