Optimisation Grade 12: Maximum Surface Area Box
TLDRThe video script explains the process of maximizing the surface area of a box with a given volume of 1000 cubic units, where the length is three times the breadth. The formula for surface area is derived and simplified using the volume constraint to express h in terms of x. The first derivative of the surface area function is taken to find the maximum value, which is achieved when x is approximately 6.06, indicating the optimal breadth for the box.
Takeaways
- π The problem is to find the value of x for a box that maximizes surface area, given a specific relationship between length and breadth.
- π The length of the box is three times the breadth, so if the breadth is x, the length is 3x.
- π’ The surface area of the box is calculated by considering all the external faces, including the top, bottom, front, and sides.
- π The formula for surface area is simplified to 8hx + 6x^2, where h is the height and x is the breadth.
- π To eliminate one variable, the volume of the box is related to the surface area by the given volume of 1000 cubic units.
- 𧩠The volume formula is 3x^2 * h, and by setting it equal to 1000, h can be expressed as 1000 / (3x^2).
- π Substituting h in the surface area formula with 1000 / (3x^2) allows for the expression of surface area solely in terms of x.
- π The resulting surface area equation is 8000x / (3x^2) + 6x^2, which simplifies to 8000/3x + 6x^2.
- π€ To find the maximum surface area, the first derivative of the surface area equation with respect to x is taken and set to zero.
- βοΈ The derivative simplifies to -8000/3x^3 + 12x, which is then set to zero to solve for x.
- π The solution to the equation 8000 = 36x^3 yields x as the cube root of (8000/36), which is approximately 6.06.
Q & A
What is the main objective of the problem presented in the script?
-The main objective is to find the value of x that maximizes the surface area of a box with a given volume and a specific relationship between its length and breadth.
What is the relationship between the length and breadth of the box as described in the script?
-The length of the box is three times the breadth. If the breadth is x, then the length is 3x.
What is the formula for the surface area of the box given in the script?
-The formula for the surface area is 2(h * x) + 6x^2 + 2(3x * h), which simplifies to 8hx + 6x^2.
How is the volume of the box related to the variables x and h in the script?
-The volume of the box is given by the product of its length, breadth, and height, which is 3x^2 * h, and it is set to be equal to 1000 cubic units.
What substitution is made to eliminate one of the variables in the surface area formula?
-The substitution made is to express h in terms of x using the volume formula, resulting in h = 1000 / (3x^2).
How is the surface area formula simplified after substituting for h?
-After substituting for h, the surface area formula is simplified to 8000x / (3x) + 6x^2, which further simplifies to 8000/3x + 6x^2.
What mathematical method is used to find the maximum surface area?
-The method used to find the maximum surface area is calculus, specifically by taking the first derivative of the surface area formula and setting it equal to zero.
What is the first derivative of the simplified surface area formula?
-The first derivative is -8000/(3x^2) + 12x, which is obtained by differentiating the simplified surface area formula with respect to x.
How is the equation set up to find the maximum surface area after taking the derivative?
-The equation is set up by equating the first derivative to zero: 0 = -8000/(3x^2) + 12x.
What is the final step in solving for x to find the maximum surface area?
-The final step is to solve the equation 8000 = 36x^3 for x, which involves dividing both sides by 36 and then taking the cube root of the result.
What is the final answer for the value of x that maximizes the surface area?
-The final answer for the value of x is approximately 6.06, which is obtained by taking the cube root of 8000/36.
Outlines
π Maximizing Surface Area of a Box
The script begins by setting up a mathematical problem to find the value of x that maximizes the surface area of a box. It's given that the length of the box is three times its breadth, and the breadth is represented by x. The script then derives the formula for the surface area of the box, considering all sides including the top and bottom. The volume of the box is also given as a thousand cubic units, leading to an equation that relates the volume to the dimensions of the box. The script proceeds to solve for the height (h) in terms of x and substitutes this back into the surface area formula, resulting in a single-variable equation in terms of x. The goal is to find the maximum surface area, which involves taking the derivative of the surface area equation with respect to x and setting it to zero to find critical points. The process involves algebraic manipulation to isolate x, ultimately leading to the solution for x that maximizes the surface area.
Mindmap
Keywords
π‘Surface Area
π‘Optimization
π‘Box Dimensions
π‘Volume
π‘First Derivative
π‘Critical Points
π‘Maximization
π‘Constraints
π‘Cubic Units
π‘Third Root
π‘Calculus
Highlights
The goal is to find the value of x that maximizes the surface area of a box.
The box has a length that is three times the breadth.
Surface area includes the top, bottom, front, back, and sides of the box.
The surface area formula is derived as 2(h*x) + 6x^2 + 6xh.
The volume of the box is given as 1000 cubic units.
Volume formula is length * breadth * height = 3x^2 * h.
Solving for h gives h = 1000 / (3x^2).
Substitute h in the surface area formula using the volume relationship.
Simplify the surface area formula to 8000/(3x) + 6x^2.
To find maximum surface area, take the first derivative and set it to zero.
Derivative of the surface area formula is -8000/(3x^2) + 12x.
Solve the derivative equation to find critical points.
Simplify the derivative equation to 8000 = 36x^3.
Divide both sides by 36 to isolate x^3.
Take the cube root of both sides to solve for x.
The final answer for x is 6.06, which maximizes the surface area.
Transcripts
Browse More Related Video
5.0 / 5 (0 votes)
Thanks for rating: