Worked example: power series from cos(x) | Series | AP Calculus BC | Khan Academy
TLDRThis video explores finding the Maclaurin series representation of the function f(x) = x^3 * cos(x^2). The speaker initially discusses the complexity of deriving this series through differentiation, emphasizing the tedious nature of calculating higher-order derivatives. Instead, they suggest leveraging the known Maclaurin series for cos(x) and adapting it for cos(x^2). By substituting and simplifying, the video demonstrates how to obtain the first five non-zero terms of the Maclaurin series for the given function, providing a more efficient and insightful approach to solving such problems.
Takeaways
- ๐งโ๐ซ The goal is to find the Maclaurin series representation for f(x) = x^3 * cos(x^2) with the first five non-zero terms.
- ๐ The Maclaurin series is a Taylor series centered at zero.
- ๐ Finding derivatives directly can be complex and tedious.
- ๐งฎ Using the known Maclaurin series for cos(x) can simplify the process.
- ๐ The Maclaurin series for cos(x) is 1 - x^2/2! + x^4/4! - x^6/6! + x^8/8! - ...
- ๐ Rewriting f(x) as x^3 * g(x^2) where g(x) = cos(x) helps in the series expansion.
- ๐ข Substitute x with x^2 in the cos(x) series to get 1 - x^4/2! + x^8/4! - x^12/6! + x^16/8! - ...
- ๐งฉ Multiply the resulting series by x^3 to obtain the Maclaurin series for f(x).
- ๐ The resulting series is x^3 - x^7/2! + x^11/4! - x^15/6! + x^19/8!
- โ This approach avoids the need for finding higher-order derivatives directly.
Q & A
What is the goal of the Maclaurin series approximation in the video?
-The goal is to find the first five non-zero terms of the Maclaurin series representation of the function f(x) = x^3 * cos(x^2).
Why might finding the Maclaurin series through derivatives be challenging for this function?
-Finding the Maclaurin series through derivatives is challenging because taking the derivatives of the function f(x) = x^3 * cos(x^2) involves the product rule and chain rule, which becomes increasingly complex and painful for higher-order derivatives.
What is a Maclaurin series?
-A Maclaurin series is a Taylor series centered at zero. It represents a function as an infinite sum of terms calculated from the values of its derivatives at zero.
What hint does the speaker provide to make finding the series easier?
-The speaker hints that knowing the Maclaurin series for cosine of x can be useful. Specifically, using the series for cos(x) to help find the series for f(x) = x^3 * cos(x^2).
What is the Maclaurin series for cos(x)?
-The Maclaurin series for cos(x) is: 1 - x^2 / 2! + x^4 / 4! - x^6 / 6! + x^8 / 8! - ... and so on.
How does substituting x^2 for x in the Maclaurin series of cos(x) help?
-Substituting x^2 for x in the Maclaurin series of cos(x) allows us to find the series for cos(x^2). This substitution transforms the series into a new polynomial which can then be multiplied by x^3 to get the series for f(x).
What is the resulting series after substituting x^2 for x in the Maclaurin series of cos(x)?
-After substituting x^2 for x, the resulting series is: 1 - x^4 / 2! + x^8 / 4! - x^12 / 6! + x^16 / 8! - ... and so on.
How do you obtain the Maclaurin series for f(x) = x^3 * cos(x^2)?
-To obtain the Maclaurin series for f(x) = x^3 * cos(x^2), you multiply the transformed series (from the previous step) by x^3. This gives: x^3 - x^7 / 2! + x^11 / 4! - x^15 / 6! + x^19 / 8! - ... and so on.
Why is it beneficial to rewrite the function in terms of known series?
-Rewriting the function in terms of known series, such as the Maclaurin series for cos(x), simplifies the process and avoids the tedious and complex task of finding high-order derivatives directly.
What is the key insight for constructing the Maclaurin series in this example?
-The key insight is that if you can express your function as a product of a polynomial and a function with a known Maclaurin series, you can substitute appropriately and multiply to find the series representation more easily.
Outlines
๐ง Understanding Maclaurin Series for a Complex Function
The speaker introduces the problem of finding the Maclaurin series representation of the function f(x) = x^3 * cos(x^2). They emphasize the goal of deriving the first five non-zero terms of the series and mention the challenges involved in calculating derivatives for the function. The video aims to provide a more efficient method by leveraging the known Maclaurin series of cos(x).
๐ Transforming and Applying Known Series
The speaker demonstrates how to transform the function using the known Maclaurin series for cos(x). By substituting x with x^2 and multiplying by x^3, they construct the Maclaurin series for the given function. This approach avoids the complexity of directly computing high-order derivatives and yields the desired first five non-zero terms. The explanation concludes with a general strategy for using known series expansions to simplify the derivation process for similar functions.
Mindmap
Keywords
๐กMaclaurin Series
๐กTaylor Series
๐กDerivatives
๐กProduct Rule
๐กCosine Function
๐กFactorial
๐กPolynomial
๐กApproximation
๐กExponentiation
๐กNon-zero Terms
๐กRe-expression
Highlights
Introduction to finding the Maclaurin series representation of a function involving x cubed times the cosine of x squared.
Explanation of the Maclaurin series as the Taylor series centered at zero.
Challenge of finding the Taylor series due to the complexity of deriving the function.
Derivation of the first derivative using the product rule and its expression.
The potential frustration of finding higher order derivatives for the Taylor series.
The strategy of evaluating derivatives at zero for coefficients in the series.
Hint to use the known Maclaurin series for cosine(x) to simplify the problem.
Reminder of the Maclaurin series for cosine(x) from a previous video.
The insight to express the function as x cubed times the square of g(x), where g(x) is cosine(x).
Method to substitute x with x squared in the known Maclaurin series to simplify calculations.
Illustration of how to distribute x cubed across the Maclaurin series of g(x) squared.
Derivation of the first five non-zero terms of the Maclaurin series for the given function.
Avoidance of brute force by re-expressing the function in terms of known series.
General strategy for finding the Maclaurin series of a function expressed as a power of x times another function.
The importance of recognizing patterns and leveraging known series to simplify complex problems.
Final expression of the first five non-zero terms of the Maclaurin series for the given function.
Conclusion emphasizing the efficiency of the method used compared to brute force.
Transcripts
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