Worked example: Maclaurin polynomial | Series | AP Calculus BC | Khan Academy
TLDRIn this instructional video, the concept of finding the second-degree Maclaurin polynomial for the function f(x) = 1/โ(x+1) is explored. The instructor guides viewers through the process of deriving the polynomial by evaluating the function and its first and second derivatives at zero. The final result is a polynomial, p(x) = 1 - 1/2x + 3/8xยฒ, which serves as an approximation for f(x) when x is near zero, providing a clear and concise explanation of the Maclaurin polynomial's application.
Takeaways
- ๐ The script is a tutorial on finding the second degree Maclaurin polynomial for a given function.
- ๐ The function in question is f(x) = 1 / โ(x + 1), and the goal is to determine its Maclaurin polynomial.
- ๐ A Maclaurin polynomial is defined as a Taylor polynomial centered at zero, which is a polynomial approximation of a function near zero.
- ๐ The form of the second degree Maclaurin polynomial is given by p(x) = f(0) + f'(0)x + f''(0)/2 * x^2.
- ๐ The first step is to evaluate the function and its derivatives at zero to find the necessary coefficients for the polynomial.
- ๐งฉ f(0) is calculated as 1 / โ1, which simplifies to 1, since the principal root of 1 is positive.
- ๐ The first derivative, f'(x), is found using the chain rule and power rule, resulting in f'(0) = -1/2.
- ๐๐ The second derivative, f''(x), is also calculated using the chain rule and power rule, yielding f''(0) = 3/4.
- ๐ข The coefficients for the Maclaurin polynomial are then substituted into the formula to obtain the polynomial: p(x) = 1 - 1/2x + 3/8x^2.
- ๐ The final result is the second degree Maclaurin polynomial for the function f(x), which can be used to approximate the function's value near zero.
Q & A
What is a Maclaurin polynomial?
-A Maclaurin polynomial is a Taylor polynomial centered at zero. It is used to approximate a function near zero by expanding it in a power series.
What is the form of the second degree Maclaurin polynomial for a function f(x)?
-The second degree Maclaurin polynomial for a function f(x) is given by p(x) = f(0) + f'(0)x + (f''(0)/2)x^2.
What is the function f(x) in the given script?
-The function f(x) is defined as f(x) = 1/โ(x + 1), which can also be written as (x + 1)^(-1/2).
How do you find the Maclaurin polynomial for a function?
-To find the Maclaurin polynomial, you need to evaluate the function and its derivatives at x = 0 and then plug these values into the polynomial form.
What is the value of f(0) for the given function?
-The value of f(0) is 1, as f(0) = 1/โ(0 + 1) = 1.
How is the first derivative of f(x) calculated?
-The first derivative of f(x), denoted as f'(x), is calculated using the chain rule and power rule. It is f'(x) = -1/2 * (x + 1)^(-3/2).
What is the value of f'(0) for the given function?
-The value of f'(0) is -1/2, as f'(0) = -1/2 * (0 + 1)^(-3/2) = -1/2.
How is the second derivative of f(x) calculated?
-The second derivative of f(x), denoted as f''(x), is calculated by differentiating f'(x) again, using the power rule and chain rule.
What is the value of f''(0) for the given function?
-The value of f''(0) is 3/4, as f''(0) = 3/4 * (0 + 1)^(-5/2) = 3/4.
What is the final form of the second degree Maclaurin polynomial for the given function f(x)?
-The final form of the second degree Maclaurin polynomial for the given function is p(x) = 1 - (1/2)x + (3/8)x^2.
Outlines
๐ข Understanding Maclaurin Polynomials
In this section, the instructor introduces the concept of the Maclaurin polynomial. A Maclaurin polynomial is a special case of a Taylor polynomial centered at zero. The main objective is to find the second-degree Maclaurin polynomial for a given function, f(x) = 1/(โ(x+1)). The instructor highlights that the polynomial will be in the form: P(x) = f(0) + f'(0)x + (f''(0)/2)xยฒ, emphasizing that for this exercise, we only need terms up to the second degree.
๐ Calculating the Function at Zero
The focus shifts to calculating f(0), the first term of the Maclaurin polynomial. The instructor substitutes x = 0 into the function f(x) = 1/(โ(x+1)), simplifying it to f(0) = 1/(โ(1)), which equals 1. This step establishes the first component of the polynomial, showing that the constant term f(0) is simply 1.
โ๏ธ Deriving the First Derivative
Here, the instructor derives the first derivative, f'(x), using the chain rule and power rule. By expressing the function as (x+1)^(-1/2), the derivative becomes f'(x) = -1/2 * (x+1)^(-3/2). Evaluating this at x = 0 gives f'(0) = -1/2, indicating that the coefficient of x in the polynomial is -1/2. This calculation shows the role of the derivative in shaping the polynomial.
๐ Calculating the Second Derivative
The instructor explains the process of finding the second derivative, f''(x), building on the previous step. Using the power rule again, f''(x) is determined as (3/4) * (x+1)^(-5/2). When x = 0, this results in f''(0) = 3/4. The term (f''(0)/2)xยฒ thus becomes (3/8)xยฒ, adding the quadratic component to the polynomial. This section emphasizes the importance of higher-order derivatives in obtaining a more accurate polynomial approximation.
๐ Formulating the Second-Degree Maclaurin Polynomial
The instructor combines the calculated values to construct the second-degree Maclaurin polynomial: P(x) = 1 - (1/2)x + (3/8)xยฒ. This polynomial serves as an approximation for the original function f(x) near x = 0. The instructor concludes by reiterating the usefulness of Maclaurin polynomials in approximating functions, especially for values close to the center point, zero.
Mindmap
Keywords
๐กMaclaurin Polynomial
๐กTaylor Polynomial
๐กSecond Degree
๐กFunction
๐กDerivative
๐กChain Rule
๐กPower Rule
๐กFactorial
๐กZeroth Derivative
๐กApproximation
Highlights
Introduction to the problem of finding the second degree Maclaurin polynomial of a given function.
Definition of a Maclaurin polynomial as a Taylor polynomial centered at zero.
Explanation of the form of the second degree Maclaurin polynomial.
Identification of the need to find the function and its first and second derivatives at zero.
Evaluation of the function \(f(x) = \frac{1}{\sqrt{x+1}}\) at zero, resulting in \(f(0) = 1\).
Derivation of the first derivative \(f'(x)\) using the chain rule and power rule.
Evaluation of the first derivative \(f'(0)\) resulting in \(f'(0) = -\frac{1}{2}\).
Derivation of the second derivative \(f''(x)\) using the chain rule and power rule.
Evaluation of the second derivative \(f''(0)\) resulting in \(f''(0) = \frac{3}{4}\).
Calculation of the second derivative at zero divided by two, yielding \(f''(0)/2 = \frac{3}{8}\).
Construction of the second degree Maclaurin polynomial using the evaluated derivatives.
Final expression of the second degree Maclaurin polynomial \(p(x) = 1 - \frac{1}{2}x + \frac{3}{8}x^2\).
Discussion on the use of the Maclaurin polynomial for approximations of the function near zero.
Emphasis on the importance of understanding the derivatives in constructing the polynomial.
Highlight of the practical applications of the Maclaurin polynomial in approximating functions.
Encouragement for viewers to pause and attempt the problem before watching the solution.
Clarification that only the second degree term is needed for this problem.
Transcripts
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