Pre Calculus - Solving System of Nonlinear Equations | Systems of Equations
TLDRThis educational video script introduces viewers to solving systems of non-linear equations, a topic that extends beyond the linear equations taught in junior high. The script provides two examples of such systems and demonstrates the use of the substitution method to find solutions. It guides through the process of isolating variables, substituting values, and simplifying equations to solve for x and y. The video also emphasizes the importance of verifying solutions by substituting them back into the original equations.
Takeaways
- π The video is about solving systems of non-linear equations, which are sets of two or more equations with at least one non-linear equation.
- π Non-linear equations are distinguished from linear ones by having variables raised to a power higher than one, such as quadratic equations.
- π The script provides two examples of non-linear systems: one with x^2 + y^2 = 25 and 3x + 4y = 0, and another with x^2 + y = 2 and y = -x + 2.
- π The substitution method is used to solve the second example, where a linear equation is manipulated to express one variable in terms of the other.
- π’ After substituting the expression for y into the non-linear equation, the script demonstrates the process of expanding and simplifying to form a quadratic equation.
- π The quadratic equation is then factored and solved for x, yielding x = 1 as one of the solutions.
- π Subsequently, the value of x is substituted back into the linear equation to solve for y, resulting in y = 1.
- π The script emphasizes the importance of checking the solution by substituting the values of x and y back into the original equations to ensure they satisfy both.
- π For the first example, the script isolates y in the linear equation to express it in terms of x, and then substitutes this into the non-linear equation to solve for x.
- π’ The solution process involves simplifying the equation to form a quadratic in terms of x, which is then solved to find the possible values of x.
- π After finding the values of x, the script shows how to find the corresponding y values using the linear equation, resulting in multiple solutions for the system.
- π£οΈ The video concludes with an invitation for viewers to ask questions in the comments and a reminder to like, subscribe, and hit the bell for updates.
Q & A
What is the main topic of the video?
-The main topic of the video is solving systems of non-linear equations.
What is a system of non-linear equations?
-A system of non-linear equations consists of two or more equations with at least one equation that is not linear, meaning the highest exponent of the variable is not one.
What are the common methods to solve systems of linear equations?
-The common methods to solve systems of linear equations are the elimination method, the substitution method, and the graphical method.
How does the degree of an equation relate to it being linear or non-linear?
-An equation is linear if the degree of the given equation is one, meaning the highest exponent of the variable is one. If the degree is higher than one, it is considered non-linear.
What substitution method does the teacher use in the video to solve the first example?
-The teacher uses the substitution method by first solving the linear equation for y and then substituting this expression for y into the non-linear equation.
In the first example, what is the process of solving for y after finding the value of x?
-After finding the value of x, the teacher substitutes this value into the linear equation (y = -x + 2) to solve for y.
What is the purpose of checking the solution in the context of the video?
-The purpose of checking the solution is to verify whether the found values of x and y satisfy both equations in the system of non-linear equations.
What is the strategy used in the second example to solve for y in terms of x?
-The strategy used in the second example is to isolate y in the linear equation (3x + 4y = 0) and express y in terms of x as y = -3x/4.
How does the teacher simplify the equation after substituting y in terms of x in the second example?
-The teacher multiplies the entire equation by 16 to eliminate the fraction and then simplifies it to a quadratic equation in terms of x.
What are the final solutions for the second example of the system of non-linear equations?
-The final solutions for the second example are (x, y) = (4, -3) and (x, y) = (-4, 3).
How can viewers get updates on the latest uploads from the channel?
-Viewers can hit the like and subscribe button and also hit the bell button to get updates on the latest uploads from the channel.
Outlines
π Introduction to Solving Non-linear Systems
The video script begins with an introduction to the topic of solving systems of non-linear equations. The instructor explains the difference between linear and non-linear equations, emphasizing that non-linear systems involve at least one equation where the highest exponent of the variable is greater than one. Two examples of non-linear systems are provided, illustrating the concept with a quadratic equation and a linear one combined, and another with a non-linear equation and a linear equation for y in terms of x.
π Substitution Method for Non-linear Systems
The second paragraph delves into the substitution method for solving non-linear systems. The instructor demonstrates how to isolate a variable in a linear equation and then substitute this expression into a non-linear equation to solve for the other variable. Using the example of the system where y is expressed in terms of x, the instructor shows the process of substitution and simplification, leading to a quadratic equation in terms of x, which is then factored and solved for x.
π Solving for x and Verifying the Solution
In the third paragraph, the instructor continues the solution process by finding the value of y using the previously determined value of x. The solution for y is found by substituting x back into one of the original equations. The instructor then explains the importance of verifying the solution by substituting the values of x and y back into both original equations to ensure they satisfy the system. The verification confirms that the solution is correct.
π§ Solving the Second Non-linear System Example
The final paragraph presents the solution to the second example of a non-linear system. The instructor chooses to isolate y in the linear equation and then substitute this expression into the quadratic equation to solve for x. After finding the values of x, the instructor proceeds to find the corresponding values of y by substituting x back into the linear equation. Two sets of solutions for x and y are obtained and presented, and the instructor encourages viewers to check the solutions in the original equations.
Mindmap
Keywords
π‘Systems of Non-Linear Equations
π‘Degree of an Equation
π‘Substitution Method
π‘Linear Equation
π‘Quadratic Equation
π‘Factoring
π‘Graphical Method
π‘Elimination Method
π‘Checking Solutions
π‘Variable
π‘Exponent
Highlights
Introduction to the topic of solving systems of non-linear equations.
Definition of a system of non-linear equations, consisting of two or more equations with at least one non-linear equation.
Explanation of linear equations and their degree, contrasting with non-linear equations.
Overview of methods to solve systems of linear equations: elimination, substitution, and graphical methods.
Two example systems of non-linear equations are presented for demonstration.
Description of the first example with a quadratic equation and a linear equation.
Description of the second example with a non-linear equation and a linear equation.
Introduction of the substitution method for solving non-linear systems, starting with the linear equation.
Step-by-step substitution process using the linear equation to solve for a variable.
Expansion of the substituted expression using the FOIL method.
Simplification of the equation to form a quadratic equation.
Factoring and solving the quadratic equation to find the value of x.
Using the found value of x to solve for y using the second equation.
Verification of the solution by substituting x and y back into the original equations.
Introduction of the second example with a different pair of equations.
Isolating y in the linear equation to temporarily solve for y in terms of x.
Substituting the expression for y into the quadratic equation to solve for x.
Simplifying and solving the resulting quadratic equation for x.
Finding the corresponding values of y for each x using the linear equation.
Consolidating the solutions for the system of equations and verifying them.
Conclusion of the tutorial with an invitation for questions and further engagement.
Transcripts
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