Physics 15 Torque Example 2 (2 of 7) Mass on Rod and Cable
TLDRThe video script presents a detailed walkthrough of solving a static torque problem. The lecturer begins by establishing that in a static problem, the sum of all forces and torques equals zero. A pivot point is chosen, and the forces acting on the system are identified: the weight of a hanging mass (mg), the weight of the beam itself (big mg), and the tension in a cable. The corresponding torques for each force are calculated based on their distances from the pivot point. The distances (d1, d2, d3) are determined using trigonometric relationships with the beam's length (L) and angles. The problem is solved algebraically by setting the sum of torques to zero and solving for the unknown tension (T) in the cable. The final answer is obtained by substituting known values and using the tangent of a 45-degree angle, resulting in a cable tension of 1372 Newtons. The summary emphasizes the importance of correctly identifying forces and torques, applying trigonometry to find distances, and performing algebraic manipulations to solve for the unknown.
Takeaways
- 📚 The problem is a statics problem, meaning no movement or acceleration is involved.
- ⚖️ The sum of all forces and torques acting on the system must be zero.
- 🔴 Clockwise torque is considered positive, and counterclockwise torque is negative.
- 📐 The torque for each force is calculated as the force multiplied by the perpendicular distance from the pivot point to the line of action of the force.
- 📐 The distances (d1, d2, d3) are crucial to determining the torques and are found using trigonometry based on the geometry of the problem.
- 🧮 The equation for the sum of torques is set to zero, and solved step by step.
- 🔢 The distances are expressed in terms of the beam's length (L) and the angle (theta) using trigonometric functions.
- 📐 The triangle formed by the beam and the forces helps in finding the distances to the line of action of each force.
- ➗ The length of the beam (L) can be canceled out from the equation since it's a common factor in every term.
- 🔄 The final equation is rearranged to solve for the tension (T) in the cable, involving the mass (M), gravitational acceleration (g), and the tangent of the angle (theta).
- 📝 The values for the mass of the hanging object, the mass of the beam, and the gravitational acceleration are substituted into the equation to find the numerical solution for the tension.
- 📊 The tangent of 45 degrees is equal to 1, simplifying the final calculation.
Q & A
What is the main principle used to solve the torque problem in the given script?
-The main principle used is that the sum of all the torques about a chosen pivot point must add up to zero in a static problem where the sum of all forces is also zero.
How are torques defined in the context of the problem?
-Torques are defined as the product of a force and the perpendicular distance from the pivot point to the line of action of that force. Clockwise torque is considered positive, and counterclockwise torque is considered negative.
What are the three forces acting on the beam in the problem?
-The three forces acting on the beam are the weight of the hanging mass (mg), the weight of the beam itself (big mg), and the tension in the cable.
How is the distance associated with each force calculated in the problem?
-The distances associated with each force (d1, d2, d3) are calculated by drawing triangles and using trigonometric relationships, such as sine and cosine, based on the angles and the length of the beam.
What is the significance of the angle theta in the problem?
-The angle theta is significant because it is used to calculate the distances d1, d2, and d3 using trigonometric functions (sine and cosine), which are then used to compute the torques and solve the problem.
How does the lecturer approach the problem algebraically?
-The lecturer first sets up the equation with the torques (T1, T2, T3) and identifies the distances (d1, d2, d3). After finding the distances, the lecturer cancels out the common length L from the equation and then divides both sides by the cosine of theta to solve for the tension T in the cable.
What is the final calculated tension in the cable?
-The final calculated tension in the cable is 1372 Newtons.
Why is it important to identify and label the distances (d1, d2, d3) from the pivot point to the line of action of each force?
-Identifying and labeling the distances is important because it helps in setting up the correct equation for the torques and ensures that the perpendicular distances are accurately represented in the calculations.
What is the role of trigonometry in solving this torque problem?
-Trigonometry plays a crucial role in calculating the distances from the pivot point to the line of action of the forces, which are necessary to compute the torques. Specifically, sine and cosine functions are used to relate the angles and sides of the triangles formed by the forces and the beam.
How does the lecturer ensure that the correct equation is written on the board?
-The lecturer ensures this by first writing the equation for the torques (T1, T2, T3) and then identifying the distances (d1, d2, d3) one by one. The讲师逐步计算每个距离,并确保它们在图形上正确标记,然后将其插入方程中,最后通过代数操作解决问题。
What is the significance of the tangent of 45 degrees in the final calculation?
-The tangent of 45 degrees is significant because it equals 1, which simplifies the final calculation of the tension in the cable. This is a result of the specific angle theta being 45 degrees, which is a common scenario in many statics problems.
Why is it necessary to draw triangles when calculating the distances associated with the forces?
-Drawing triangles is necessary because it helps visualize and apply trigonometric principles to find the perpendicular distances from the pivot point to the line of action of each force. These distances are essential for calculating the torques.
How does the lecturer ensure that the algebraic manipulation of the equation is done correctly?
-The lecturer ensures this by systematically identifying each torque, calculating the associated distances, and then carefully performing algebraic operations, such as canceling out common terms and dividing by the cosine of theta, to isolate and solve for the unknown tension in the cable.
Outlines
🔍 Static Torque Problem Analysis
The paragraph introduces a static torque problem where the sum of all forces and torques equals zero. The lecturer chooses a pivot point and identifies three forces acting on a beam: the weight of a hanging mass (mg), the weight of the beam itself (big mg), and the tension in a cable. The concept of torque is explained, with clockwise torque considered positive and counterclockwise negative. The distances from the forces' lines of action to the pivot point (d1, d2, d3) are identified as crucial for calculating torques. The problem is approached step by step, starting with defining the forces and their distances, and then calculating the torques around the chosen pivot point.
📐 Calculating Distances and Solving the Torque Equation
This paragraph delves into calculating the distances (d1, d2, d3) from the forces' lines of action to the pivot point using trigonometric relationships in triangles formed by the beam and the forces. The讲师 (lecturer) uses the sine function to find d1, which is opposite an angle theta in a triangle where the adjacent side is 4/5 the length of the beam (L). For d2, the lecturer uses the sine of the angle theta again, but with the hypotenuse being half the length of the beam (L/2). The distance d3 is found using the cosine of the angle theta, as it is adjacent to the angle. After establishing the distances, the lecturer simplifies the torque equation by canceling out the common factor L and rearranging the terms to solve for the tension in the cable (T). The final step involves substituting the given values for the masses and gravitational acceleration to calculate the tension in the cable, which is found to be 1372 Newtons after using a calculator.
Mindmap
Keywords
💡Torque
💡Static Problem
💡Pivot Point
💡Forces Acting
💡Distance to Line of Action
💡Tension in the Cable
💡Clockwise and Counterclockwise Torque
💡Sum of Torques
💡Trigonometric Functions
💡Equation of Statics
💡Mass and Weight
Highlights
The lecture introduces a static torque problem where the sum of all forces and torques is zero.
The concept of summing torques about a chosen pivot point to zero is used to solve the problem.
Identifying forces acting on the problem is the first step, including the weight of the mass and the beam, and the tension in the cable.
Torque is calculated as the product of force and the perpendicular distance from the pivot point to the line of action of the force.
Clockwise torque is defined as positive and counterclockwise as negative in the context of this problem.
The distance associated with each force (d1, d2, d3) is calculated using trigonometric relationships based on the geometry of the problem.
The triangle formed by the beam and the forces is used to determine distances d1, d2, and d3.
Angles within the triangles are used to apply trigonometric functions (sine and cosine) to find the distances.
The sum of the torques equation is set up with the identified forces and their respective distances.
The length of the beam (L) is factored out from the equation as a common factor.
The tension in the cable (T) is solved by rearranging the torque equation and applying trigonometric identities.
The tangent of the angle (theta) is used to simplify the equation, which equals 1 for a 45-degree angle.
The numerical values for the mass of the hanging object (50 kg) and the beam (200 kg) are used to calculate the tension.
The acceleration due to gravity (g = 9.8 m/s²) is included in the final calculation of the tension.
The final answer for the tension in the cable is derived using algebraic manipulation and substitution of known values.
The lecture emphasizes the importance of correctly setting up the equation and using algebra to solve for the unknowns.
A step-by-step approach is recommended to avoid confusion and ensure the accuracy of the final solution.
Transcripts
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