A Range Equation Problem with Two Parts
TLDRIn the video, Mr. P attempts to throw a ball into a bucket. Initially, the ball falls short by 34 cm. Using the Range Equation, the team calculates the required initial speed and launch angle for a successful throw. They find that the second attempt should be thrown at 43 degrees, but also note that complementary angles (47 degrees) would work due to the symmetry of projectile motion. The video combines physics problem-solving with a playful tone, culminating in a practical demonstration of the solution.
Takeaways
- πΎ Mr. P attempts to throw a ball into a bucket 581 centimeters away with an initial angle of 55 degrees, but falls short by 34 centimeters.
- π The Range Equation is used to solve projectile motion problems where the displacement in the Y direction is zero, making it suitable for this scenario.
- π’ The first range (first attempt) is calculated by subtracting the short distance (34 cm) from the total distance (581 cm), converting it to meters (5.47 m).
- π The magnitude of the initial velocity (v_sub_i) is determined by using the Range Equation and known values, resulting in 7.55675 meters per second.
- π For the second attempt, the initial speed remains the same, and the total distance is the bucket's distance (5.81 meters).
- π The Range Equation is again utilized, this time solving for the launch angle of the second attempt, which is found to be approximately 43 degrees.
- π Complementary angles (angles that add up to 90 degrees) are acknowledged as both providing the same range, suggesting an alternative launch angle of 47 degrees.
- π€ The problem-solving process emphasizes the importance of understanding the physics behind projectile motion and the application of the Range Equation.
- π₯ Collaboration and dialogue between characters help to clarify concepts and steps in solving the problem, highlighting the value of teamwork in problem-solving.
- π₯ The video script format provides a narrative structure to learning, making complex concepts more accessible and engaging for the audience.
- π The video concludes with a practical demonstration of the solution, reinforcing the theoretical concepts with a real-world application.
Q & A
What is the problem that Mr. P is trying to solve?
-Mr. P is trying to find the correct angle to throw a ball so that it lands in a bucket located 581 centimeters away from him horizontally, after having failed to do so with an initial throw at a 55-degree angle.
What is the significance of the bucket's height in this problem?
-The height of the bucket is significant because the ball is always released at the same height as the top of the bucket, which means the displacement in the Y direction is zero, allowing the use of the Range Equation.
What is the Range Equation mentioned in the script?
-The Range Equation states that the range of a projectile equals the magnitude of the initial velocity (or initial speed) squared, times the sine of two times the launch angle, divided by the acceleration due to gravity.
How do they determine the initial speed for the first throw?
-They use the Range Equation for the first throw, knowing the first range (547 cm), the first launch angle (55 degrees), and the acceleration due to gravity (9.81 m/s^2), and solve for the unknown initial speed (v_sub_i).
What is the calculated initial speed for Mr. P's throws?
-The calculated initial speed is approximately 7.55675 meters per second, found by taking the square root of the product of the acceleration due to gravity and the first range, divided by the sine of two times the first launch angle.
What is the total distance to the bucket for the second attempt?
-The total distance to the bucket for the second attempt is 581 centimeters, which is converted to 5.81 meters for use in the Range Equation.
How is the launch angle for the second attempt determined?
-The launch angle for the second attempt is determined by rearranging the Range Equation to solve for the sine of two times the launch angle, and then taking the inverse sine. The calculated angle is 43 degrees, but it is noted that the complementary angle of 47 degrees would also work due to the property of complementary angles having the same range.
What is the diameter of the basketball used in the problem?
-The diameter of the basketball used in the problem is 23 and a half centimeters.
What is the diameter of the bucket in the problem?
-The diameter of the bucket is 30 centimeters.
Why are there two correct launch angles for this problem?
-There are two correct launch angles because complementary angles, which add up to 90 degrees, will both result in the same range when thrown.
What is the final answer for the launch angle that will land the ball in the bucket?
-The final answer for the launch angle is either 43 or 47 degrees, as both angles are complementary and will result in the ball landing in the bucket.
Outlines
π Solving the Range Equation Problem
This paragraph introduces a two-step Range Equation problem where Mr. P attempts to throw a ball into a bucket. The first throw falls short, and the group discusses using the Range Equation to determine the correct angle for the second throw. The problem is set up with the given conditions: initial horizontal distance, angle of projection, and the fact that the ball is released at the same height as the top of the bucket. The Range Equation is derived and used to calculate the unknown initial speed, which remains constant for both throws. The process of solving for the launch angle is explained, with the group working through the physics and math involved.
π― Calculating the Correct Launch Angle
In this paragraph, the group continues their discussion on the Range Equation, focusing on solving for the launch angle that will allow the ball to land in the bucket. They use the previously calculated initial speed and apply it to the second attempt, where the range is known to be the total distance to the bucket. The calculations lead to a specific angle, but the group also considers the possibility of complementary angles providing the same range, leading to two potential correct answers. The paragraph concludes with a practical demonstration of the solution and a reflection on the learning process.
Mindmap
Keywords
π‘Range Equation
π‘Projectile Motion
π‘Initial Velocity
π‘Launch Angle
π‘Acceleration Due to Gravity
π‘Displacement
π‘Trigonometry
π‘Complementary Angles
π‘Inverse Sine
π‘Parabolic Trajectory
π‘Projectile Range
Highlights
Mr. P throws a ball toward a bucket, which is 581 centimeters away.
The ball is thrown at an initial angle of 55 degrees above the horizontal.
The ball falls 34 centimeters short of the bucket on the first throw.
The problem requires finding the angle to throw the ball so it lands in the bucket when the initial speed is the same.
The Range Equation is identified as the appropriate method to solve the problem.
The displacement in the Y direction is zero for the second throw, allowing the use of the Range Equation.
The range for the first throw is calculated as 547 centimeters.
The first throw's range is converted to meters for calculation purposes.
The magnitude of the initial velocity is the unknown variable for the first throw.
The initial speed is determined to be 7.55675 meters per second for the first throw.
The second throw's range is the total distance to the bucket, 5.81 meters.
The launch angle for the second throw is calculated using the Range Equation.
The calculated launch angle for the second throw is 43 degrees.
It is noted that complementary angles can give the same range, suggesting two possible correct angles.
The correct answer includes either 43 or 47 degrees as the launch angle for the second throw.
The practical application of the problem involves throwing a basketball into a bucket.
The problem-solving process is demonstrated through a collaborative and engaging conversation.
Transcripts
Browse More Related Video
(Part 2 of 2) An Introductory Projectile Motion Problem with an Initial Horizontal Velocity
Nerd-A-Pult - An Introductory Projectile Motion Problem
Understanding the Range Equation of Projectile Motion
(Part 1 of 2) An Introductory Projectile Motion Problem with an Initial Horizontal Velocity
Projectile Motion: Shooting a Basketball Problem
AP Physics B Kinematics Presentation #77
5.0 / 5 (0 votes)
Thanks for rating: