AP Calculus AB - 1.8 Determining Limits Using the Squeeze Theorem
TLDRIn this calculus lesson, Mr. Bortnick introduces the Squeeze Theorem, also known as the Sandwich Theorem, which is a method for determining limits when direct substitution is not possible. He explains the theorem's conditions and demonstrates its application through several examples, including a limit involving cosine and x-squared. The lesson also covers scenarios where the theorem does not apply due to unequal limit values. Mr. Bortnick encourages students to practice with provided problems and seek clarification during class or office hours.
Takeaways
- π The topic of the day is the Squeeze Theorem, also known as the Sandwich Theorem, which is used to determine limits in calculus.
- π οΈ The Squeeze Theorem states that if a function \( f(x) \) is squeezed between two other functions \( g(x) \) and \( h(x) \), and the limits of \( g(x) \) and \( h(x) \) as \( x \) approaches a certain value \( a \) are equal, then the limit of \( f(x) \) is also equal to that value.
- β οΈ The theorem can only be applied if the 'if' part of the statement is true, meaning \( g(x) \leq f(x) \leq h(x) \) and the limits of \( g(x) \) and \( h(x) \) are the same.
- π The first example demonstrates the theorem by showing that the limit of \( x^2 \cdot \cos(1/x^2) \) as \( x \) approaches 0 is 0, using the fact that the cosine function oscillates between -1 and 1.
- π« The second example shows a case where the Squeeze Theorem cannot be applied because the limits of \( g(x) \) and \( h(x) \) as \( x \) approaches 2 are not equal.
- π― The third example successfully applies the Squeeze Theorem to find that the limit of \( f(x) \) as \( x \) approaches 0 is 3, given that \( \cos(\pi/(2x+2)) \leq f(x) \leq x^2 + 3 \) and the limits of the outer functions are equal.
- π€ The final set of problems asks to determine whether the Squeeze Theorem can be applied to given inequalities to find limits as \( x \) approaches 0, with some being applicable and others not due to the limits of the outer functions not matching.
- π In the examples, the limits of functions are evaluated using direct substitution where possible, and the Squeeze Theorem is applied when the conditions are met.
- π The importance of understanding the behavior of functions, such as the range of the cosine function, is highlighted for effectively using the Squeeze Theorem.
- π The script encourages students to practice with the provided problems and to use class time and office hours for clarification of doubts.
Q & A
What is the Squeeze Theorem also known as?
-The Squeeze Theorem is sometimes referred to as the Sandwich Theorem or the Pinching Theorem.
What is the basic premise of the Squeeze Theorem?
-The Squeeze Theorem states that if a function f(x) is surrounded by two other functions g(x) and h(x), such that g(x) β€ f(x) β€ h(x), and the limits of g(x) and h(x) as x approaches a certain value are equal, then the limit of f(x) as x approaches that value is also equal to that limit.
What is an example of a trigonometric function that cannot be solved using direct substitution?
-An example given in the script is the limit as x approaches 0 of x squared times cosine of 1 over x squared, which cannot be solved using direct substitution due to division by zero.
What is the range of the cosine function?
-The range of the cosine function is between -1 and 1, inclusive.
How does the Squeeze Theorem help in finding the limit of the function x squared times cosine of 1 over x squared as x approaches 0?
-The Squeeze Theorem helps by establishing that the function is bounded between -x squared and x squared, both of which have a limit of 0 as x approaches 0, thus the limit of the original function must also be 0.
What is the significance of the limits of g(x) and h(x) in the Squeeze Theorem?
-The limits of g(x) and h(x) must be equal and approach the same value as x approaches the point in question for the Squeeze Theorem to be applicable and conclude the limit of f(x).
Why can't the Squeeze Theorem be used to find the limit as x approaches 2 of a function f(x) when g(x) = -x squared + 2x - 3 and h(x) = 2x + 1?
-The Squeeze Theorem cannot be used in this case because the limits of g(x) and h(x) as x approaches 2 are not equal, which violates the condition that the limits must be the same for the theorem to apply.
What is the limit as x approaches 0 of the function f(x) given g(x) = cosine of pi over 2x + 2 and h(x) = x squared + 3?
-The limit as x approaches 0 of f(x) is 3, as both g(x) and h(x) evaluate to 3 at x = 0, satisfying the conditions of the Squeeze Theorem.
What conditions must be met for the Squeeze Theorem to be applicable for a function f(x) as x approaches zero?
-For the Squeeze Theorem to be applicable, there must be functions g(x) and h(x) such that g(x) β€ f(x) β€ h(x) for all x in a neighborhood of zero, and the limits of g(x) and h(x) as x approaches zero must be equal.
Why does the Squeeze Theorem apply to the limit as x approaches 0 of g(x) = -x cubed + 1 and h(x) = x cubed + 1?
-The Squeeze Theorem applies because both g(x) and h(x) evaluate to 1 as x approaches 0, indicating that the limit of f(x), if it exists and is squeezed between g(x) and h(x), must also be 1.
Outlines
π Introduction to the Squeeze Theorem
This paragraph introduces the concept of the Squeeze Theorem, also known as the Sandwich Theorem, in the context of calculus. The theorem is explained as a method to determine limits when direct substitution is not possible due to division by zero or other undefined expressions. The basic premise is that if a function 'f(x)' is 'squeezed' between two other functions 'g(x)' and 'h(x)', and both 'g(x)' and 'h(x)' have the same limit 'l' as 'x' approaches a certain value 'a', then 'f(x)' must also have the limit 'l'. The explanation includes a step-by-step breakdown of the conditions required to apply the theorem and an example involving the limit of 'x^2 * cos(1/x^2)' as 'x' approaches 0, which cannot be solved through direct substitution but can be determined using the Squeeze Theorem.
π Applying the Squeeze Theorem to Example Problems
The second paragraph delves into applying the Squeeze Theorem to solve specific calculus problems. It starts with an example of finding the limit of 'x^2 * cos(1/x^2)' as 'x' approaches 0, using the known range of the cosine function to establish the bounds for the squeeze. The paragraph then discusses two additional problems involving functions 'g(x)' and 'h(x)', and a function 'f(x)' that is bounded by them. The first example demonstrates the successful application of the theorem, concluding that the limit of 'f(x)' as 'x' approaches 2 is 0. The second example shows a case where the theorem cannot be applied because the limits of 'g(x)' and 'h(x)' as 'x' approaches 2 are not equal, thus the limit of 'f(x)' cannot be determined using the Squeeze Theorem.
π Further Exploration of the Squeeze Theorem
The third paragraph continues the exploration of the Squeeze Theorem with additional examples. It discusses the limit of 'f(x)' as 'x' approaches 0, where 'f(x)' is bounded by 'cos(pi/(2x) + 2)' and 'x^2 + 3'. The limits of the bounding functions are evaluated, and it is shown that they are equal, allowing the application of the Squeeze Theorem to conclude that the limit of 'f(x)' is 3. The paragraph also addresses a set of problems where the theorem's applicability is questioned for different inequalities. It explains which inequalities can be used with the theorem based on whether the limits of the bounding functions are the same, and which cannot, providing clear criteria for the theorem's use.
Mindmap
Keywords
π‘Squeeze Theorem
π‘Limit
π‘Continuity
π‘Cosine Function
π‘Periodic Function
π‘Direct Substitution
π‘Inequality
π‘Conditional Statement
π‘Graphing Calculator
π‘Trigonometric Rules
Highlights
Introduction to the Squeeze Theorem, also known as the Sandwich Theorem or Pinching Theorem, and its formal definition.
Explanation of how the Squeeze Theorem works with three functions, where the middle function is 'squeezed' between the other two.
Conditional statement aspect of the Squeeze Theorem, requiring all conditions to be true before reaching a conclusion.
Practical example of using the Squeeze Theorem to find the limit of a function involving cosine, where direct substitution fails.
Utilization of the range of the cosine function (-1 to 1) to set up the inequality for the Squeeze Theorem.
Multiplication of the inequality by x squared to fit the form required for the Squeeze Theorem application.
Evaluation of limits for the outer functions in the inequality to determine the limit of the middle function.
Conclusion that the limit of x squared times cosine of 1 over x squared as x approaches 0 is 0, using the Squeeze Theorem.
Second example with functions g(x) and h(x), where the Squeeze Theorem is applied to find the limit as x approaches 2 of an unknown function f(x).
Demonstration that the Squeeze Theorem cannot be applied if the limits of the outer functions are not equal.
Third example with functions g(x) and h(x) defined differently, and the successful application of the Squeeze Theorem to find the limit as x approaches 0 of f(x).
Final conclusion that the limit as x approaches 0 of f(x) equals 3, based on the equality of the limits of the outer functions.
Discussion of a set of problems where the applicability of the Squeeze Theorem is to be determined, not the limit itself.
Analysis of inequalities to determine if the Squeeze Theorem can be used, based on whether the limits of the outer functions are the same.
Examples where the Squeeze Theorem does not apply due to the limits of the outer functions not being equal.
Examples where the Squeeze Theorem does apply, leading to the determination of the limit of the function as x approaches 0.
Final note on the importance of checking the equality of the limits for the Squeeze Theorem to be applicable.
Encouragement for students to practice problems, check answers, and bring questions to class for further discussion.
Transcripts
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