Zain does Partial Fractions
TLDRIn this educational video, Zayn Walker demonstrates the process of integration by partial fractions. Starting with the equation \( \frac{5 - x}{(2x - 1)(x + 1)} \), he factors the denominator and sets up the partial fraction decomposition. By plugging in specific values for x to solve for constants a and b, he finds \( a = 3 \) and \( b = -2 \). Walker then integrates the simplified expression, resulting in \( \frac{3}{2} \ln|2x - 1| - 2\ln|x + 1| \), offering a concise explanation suitable for students preparing for exams.
Takeaways
- ๐ The video is about teaching the method of integration by partial fractions.
- ๐ The first step is to factor the denominator of the given integral equation.
- ๐ The given integral is of the form (5 - x) / ((2x - 1)(x + 1)) which is factored into (5 - x) / [(x - 1/2)(2x + 1)].
- ๐ The next step involves setting up the equation for partial fractions: A / (2x - 1) + B / (x + 1).
- ๐ Multiply the entire equation by the denominator to simplify and find the values of A and B.
- ๐ To find B, substitute x = -1 into the simplified equation, resulting in B = -3.
- ๐ To find A, substitute x = 1/2 into the simplified equation, resulting in A = 3.
- ๐ After finding A and B, rewrite the integral with the identified constants.
- ๐ The integral is then rewritten as 3 / (2x - 1) - 2 / (x + 1).
- ๐งฎ The final step is to integrate each term separately, resulting in 3/2 * ln|2x - 1| - 2 * ln|x + 1|.
- ๐ The final answer is left as an indefinite integral, without applying limits for a definite integral.
Q & A
What is the first step in solving an integral by partial fractions according to the video?
-The first step is to factor the denominator of the equation.
How is the denominator factored in the example provided?
-The denominator is factored into (2x - 1)(x + 1).
What form does the equation take after factoring the denominator?
-The equation becomes 5 - x over (2x - 1)(x + 1) equals A over (2x - 1) plus B over (x + 1).
What is the next step after rewriting the equation with partial fractions?
-The next step is to multiply both sides of the equation by the common denominator, (2x - 1)(x + 1).
How do you determine the values of A and B?
-You determine the values of A and B by plugging in values for x that simplify the equations. For example, setting x = -1 to solve for B and x = 1/2 to solve for A.
What is the value of B when x = -1?
-When x = -1, B is determined to be -2.
What is the value of A when x = 1/2?
-When x = 1/2, A is determined to be 3.
How is the original integral expressed with the determined values of A and B?
-The original integral is expressed as the integral of (3/(2x - 1)) - (2/(x + 1)) dx.
What is the result of integrating the terms separately?
-The result of integrating the terms separately is 3/2 ln|2x - 1| - 2 ln|x + 1|.
What should be done if the integral is definite?
-If the integral is definite, you should plug in the upper and lower bounds for x to find the actual value.
Outlines
๐ Introduction to Partial Fractions Integration
Zayn Walker begins a tutorial on partial fractions integration with a friendly greeting to the audience. He introduces the concept by explaining the importance of factoring the denominator of the given integral equation, which in this case is '5 - x' over '2x - 1' and 'x + 1'. He then demonstrates the setup for the partial fraction decomposition by multiplying the equation by the factored denominator to simplify the process of finding the constants 'a' and 'b'.
Mindmap
Keywords
๐กIntegration
๐กPartial Fractions
๐กFactor
๐กEquation
๐กIntegral
๐กMultiply
๐กCancel Out
๐กCoefficients
๐กPlug In
๐กNatural Logarithm
๐กAbsolute Value
Highlights
Introduction to the process of integration by partial fractions.
Writing down the equation and factoring the denominator.
Factored form of the denominator: (5 - x)(2x - 1)(x + 1).
Multiplying the equation by the denominator to simplify.
Setting up the equation for partial fractions: A/(2x - 1) + B/(x + 1).
Multiplying through by the denominator to eliminate fractions.
Rewriting the equation as 5 - x = A(x + 1) + B(2x - 1).
Choosing values for x to solve for A and B.
Solving for B by setting x = -1.
Finding B = -2 from the equation 6 = B(-3).
Solving for A by setting x = 1/2.
Calculating A from the equation 9/2 = A(3/2).
Determining A = 3 from the simplified equation.
Substituting A and B back into the original integral.
Setting up the integral of 3/(2x - 1) - 2/(x + 1).
Integrating the partial fractions to get the final answer.
Final answer: 3/2 ln|2x - 1| - 2 ln|x + 1|.
Explanation that the process is complete and the integral is integratable.
Note on handling definite integrals by plugging in values for x.
Conclusion and encouragement for the test.
Transcripts
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