Worked example: Using the reaction quotient to predict a pressure change | Khan Academy
TLDRThe video explains how to determine the change in total pressure in a reaction vessel as it approaches equilibrium. Using a reaction quotient (Q), the video demonstrates that Q is less than the equilibrium constant (K), indicating the system is not at equilibrium. As the reaction shifts to produce more products, the number of gas molecules decreases, leading to a reduction in total pressure. The explanation is broken down into calculating Q, comparing it to K, and understanding the resulting shift in reaction dynamics.
Takeaways
- ๐ The reaction vessel contains 1.2 moles of CO, 1.5 moles of H2, and 2.0 moles of CH3OH.
- ๐ CO reacts with H2 in a 1:2 ratio to produce CH3OH, and the reaction is reversible.
- ๐งช The equilibrium constant (K) for the reaction is 14.5 at a constant temperature.
- ๐ To determine if the system is at equilibrium, the reaction quotient (Q) is calculated.
- ๐ Q is calculated using the concentrations of CO, H2, and CH3OH, which are 1.2 M, 1.5 M, and 2.0 M respectively.
- ๐งฎ Q is found to be 0.74, which is less than K (14.5), indicating the system is not at equilibrium.
- โก๏ธ Since Q < K, the reaction will shift towards the products to reach equilibrium.
- โ๏ธ As the reaction shifts towards the products, the total pressure in the system will decrease.
- ๐ฌ The decrease in total pressure is due to the reduction in the number of gas molecules as the reaction progresses towards equilibrium.
- ๐ The system initially has 3 moles of reactant gas and 1 mole of product gas, favoring the side with fewer gas molecules as it shifts to equilibrium.
Q & A
What is the initial concentration of carbon monoxide in the reaction vessel?
-The initial concentration of carbon monoxide is 1.2 M (molar).
What does the equilibrium constant (Kc) of 14.5 indicate about the reaction?
-The equilibrium constant (Kc) of 14.5 indicates the ratio of product to reactant concentrations at equilibrium, with a higher value suggesting the reaction favors the formation of products.
How is the reaction quotient (Q) calculated for this reaction?
-The reaction quotient (Q) is calculated using the formula Q = [CH3OH] / ([H2]^2 * [CO]), where the concentrations of methanol, hydrogen, and carbon monoxide are used.
What is the significance of Q being less than K in this reaction?
-Q being less than K indicates that the reaction is not at equilibrium and will shift to produce more products to reach equilibrium.
How do you determine if the system is at equilibrium using Q and K?
-By comparing Q to K: if Q = K, the system is at equilibrium; if Q < K, the system will shift to produce more products; if Q > K, the system will shift to produce more reactants.
Why will the total pressure decrease as the system approaches equilibrium?
-The total pressure will decrease because the reaction shifts to favor the side with fewer gas molecules (products), reducing the total number of gas molecules and thus the pressure.
How do you calculate the initial concentrations of the gases in the reaction vessel?
-The initial concentrations are calculated by dividing the number of moles of each gas by the volume of the vessel (1 liter), making the concentration equal to the number of moles.
What does the number line representation of Q and K help visualize?
-The number line helps visualize the relative positions of Q and K, showing how the reaction will shift (towards products or reactants) to reach equilibrium.
What is the relationship between the number of gas molecules and total pressure in the system?
-The total pressure is directly related to the number of gas molecules in the system; more gas molecules result in higher pressure, and fewer gas molecules result in lower pressure.
What initial information is given about the quantities of the gases in the reaction vessel?
-The reaction vessel contains 1.2 moles of carbon monoxide, 1.5 moles of hydrogen gas, and 2.0 moles of methanol gas.
Outlines
๐ Initial Reaction Analysis and Equilibrium Determination
This paragraph introduces a chemical reaction in a one-liter vessel with given moles of carbon monoxide, hydrogen, and methanol gases. It explains the reversible nature of the reaction and the use of the reaction quotient 'Q' to determine if the system is at equilibrium. The equilibrium constant 'K' is provided, and the initial concentrations are calculated based on the moles and volume. The calculation of 'Q' reveals that the system is not at equilibrium since 'Q' is less than 'K', indicating that the reaction will proceed to produce more products, thus changing the pressures within the system.
๐ Predicting Pressure Change Towards Equilibrium
The second paragraph delves into the implications of the reaction quotient 'Q' being less than the equilibrium constant 'K'. It discusses how the system will shift towards the production of more methanol to reach equilibrium. This shift is visualized on a number line to show the relative values of 'Q' and 'K'. The paragraph explains that the reaction will favor the side with fewer gas molecules, which in this case, are the products. Consequently, as the reaction progresses towards equilibrium, the total pressure will decrease due to the reduction in the number of gas molecules in the system.
Mindmap
Keywords
๐กReaction Vessel
๐กMoles
๐กChemical Equilibrium
๐กEquilibrium Constant (K)
๐กReaction Quotient (Q)
๐กConcentration
๐กStoichiometric Ratio
๐กTotal Pressure
๐กLe Chatelier's Principle
๐กMole Ratio
๐กPartial Pressure
Highlights
A one litre reaction vessel contains 1.2 moles of carbon monoxide, 1.5 moles of hydrogen gas, and 2.0 moles of methanol gas.
The reaction between carbon monoxide and hydrogen to produce methanol is reversible.
The equilibrium constant for the reaction is 14.5 at a certain temperature.
The system's temperature remains constant throughout the process.
The reaction quotient 'Q' is calculated using the product concentration of methanol divided by the concentration of hydrogen squared and carbon monoxide.
Initial concentrations are equal to the number of moles due to the one-liter volume.
Initial concentrations are 1.2 molar for carbon monoxide, 1.5 molar for hydrogen, and 2.0 molar for methanol.
The calculated reaction quotient 'Q' at the initial state is 0.74.
'Q' is not equal to 'KC', indicating the system is not at equilibrium.
The system will change pressures as it attempts to reach equilibrium.
The reaction quotient 'Q' is less than the equilibrium constant 'K', suggesting a shift towards products.
The reaction will shift to favor the production of more products to reach equilibrium.
The total pressure is related to the moles of gas in the system.
Shifting to favor the reactants, which have fewer gas molecules, will reduce the total pressure.
As the reaction approaches equilibrium, the total pressure will decrease due to the reduction in gas molecules.
The reaction quotient 'Q' being less than 'K' is the reason for the decrease in total pressure.
Transcripts
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