Limiting Reactant Practice Problem (Advanced)

Tyler DeWitt
8 Oct 201513:48
EducationalLearning
32 Likes 10 Comments

TLDRThe video script presents a complex chemistry problem involving the calculation of limiting and excess reactants. It guides viewers through the process of converting grams of aluminum and chlorine to moles, determining chlorine as the limiting reactant, and calculating the maximum amount of AlCl3 that can be produced. The script also explains how to find the excess reactant and the remaining amount of aluminum, emphasizing the importance of using moles in stoichiometric calculations.

Takeaways
  • 🔍 The problem involves determining the limiting reactant and excess reactant in a chemical reaction between aluminum (Al) and chlorine (Cl2) to produce aluminum chloride (AlCl3).
  • 📝 The given equation is essential for solving the problem, and the reactants are Al and Cl2, with AlCl3 as the product.
  • 📚 The first step is to convert the mass of reactants from grams to moles using their respective molar masses.
  • 🧪 Molar mass of aluminum is 26.98 g/mol, and for Cl2, it is 70.90 g/mol. These are used as conversion factors to find the moles of each reactant.
  • 📉 The limiting reactant is determined by comparing the moles of reactants needed to completely react with each other, based on the stoichiometry of the reaction.
  • ⚖️ To find the limiting reactant, calculate the moles of Cl2 needed to react with all Al and vice versa, using the reaction's stoichiometric ratios (2:3 for Al to Cl2).
  • 🏁 The reactant that runs out first is the limiting reactant; in this case, Cl2 is the limiting reactant because there is not enough Cl2 to react with all the available Al.
  • 🔢 The maximum amount of AlCl3 that can be produced is determined by the moles of the limiting reactant, which in this case is Cl2.
  • ⚗️ The molar mass of AlCl3 (133.33 g/mol) is used to convert the moles of AlCl3 produced back into grams.
  • 🧐 The excess reactant is identified by comparing the amount of Al used with the maximum amount that could react with the limiting reactant, Cl2.
  • 📊 The leftover moles of the excess reactant (Al) are calculated and then converted back to grams to find the mass of excess Al remaining after the reaction.
Q & A

  • What is the main topic of the practice problem discussed in the script?

    -The main topic is determining the limiting reactant and excess reactant in a chemical reaction, specifically for the production of AlCl3 using aluminum (Al) and chlorine (Cl2).

  • What is the first step to solve a limiting reactant problem?

    -The first step is to convert the given masses of reactants from grams to moles using their respective molar masses.

  • What is the molar mass of aluminum (Al) used in the script?

    -The molar mass of aluminum is 26.98 grams per mole.

  • How many moles of aluminum are in 114 grams?

    -There are 4.23 moles of aluminum in 114 grams.

  • What is the molar mass of chlorine gas (Cl2) used in the script?

    -The molar mass of chlorine gas is 70.90 grams per mole.

  • How many moles of chlorine gas are in 186 grams?

    -There are 2.62 moles of chlorine gas in 186 grams.

  • How do you determine which reactant is the limiting reactant?

    -You determine the limiting reactant by calculating how many moles of the other reactant would be needed to use up all of one reactant, and then comparing these amounts to what is actually available.

  • What is the stoichiometric ratio between aluminum and chlorine in the formation of AlCl3?

    -The stoichiometric ratio between aluminum and chlorine in the formation of AlCl3 is 2 moles of Al to 3 moles of Cl2.

  • How many moles of chlorine are needed to react with all the available aluminum?

    -To react with all 4.23 moles of aluminum, 6.35 moles of chlorine are needed.

  • How many moles of aluminum are needed to react with all the available chlorine?

    -To react with all 2.62 moles of chlorine, 1.75 moles of aluminum are needed.

  • Which reactant is determined to be the limiting reactant in the script?

    -Chlorine (Cl2) is determined to be the limiting reactant because there is not enough chlorine to react with all the available aluminum.

  • How many grams of AlCl3 can be produced with the given amounts of Al and Cl2?

    -With the given amounts of Al and Cl2, 233 grams of AlCl3 can be produced.

  • What is the molar mass of AlCl3 used in the script to convert moles to grams?

    -The molar mass of AlCl3 is 133.33 grams per mole.

  • Which reactant is in excess and how much of it is left over after the reaction?

    -Aluminum is the excess reactant, with 66.9 grams left over after the reaction.

Outlines
00:00
🧪 Determining the Limiting Reactant in a Chemical Reaction

This paragraph introduces a complex chemistry problem involving the concept of limiting and excess reactants. The goal is to calculate the maximum amount of AlCl3 that can be produced using 114 grams of aluminum (Al) and 186 grams of chlorine (Cl2). The paragraph explains the importance of identifying the limiting reactant by converting grams to moles using the molar mass of each element. It details the process of using the stoichiometric equation to find out which reactant is in excess and how much of it remains after the reaction.

05:04
🔍 Calculating Moles to Identify the Limiting Reactant

The second paragraph delves into the calculations required to determine the limiting reactant. It explains how to convert the given masses of aluminum and chlorine gas into moles using their respective molar masses. The paragraph then uses the stoichiometric ratio from the chemical equation to calculate the moles of each reactant needed to consume the other completely. By comparing the calculated moles with the actual moles available, the paragraph concludes that chlorine is the limiting reactant because there is not enough Cl2 to react with all the aluminum present.

10:05
📊 Converting Moles to Grams and Finding Excess Reactant

The final paragraph focuses on determining the theoretical yield of AlCl3 based on the limiting reactant, chlorine, and converting the moles of AlCl3 produced back into grams using its molar mass. It also addresses how to calculate the amount of excess reactant, in this case, aluminum, by subtracting the amount of aluminum that reacted from the total amount initially present. The paragraph concludes with the calculation of the remaining grams of aluminum, thus solving the problem by providing both the maximum yield of AlCl3 and the quantity of excess aluminum.

Mindmap
Keywords
💡Limiting Reactant
The limiting reactant is the substance that is completely consumed during a chemical reaction, determining the maximum amount of product that can be formed. In the video, the concept is central to solving the problem, where chlorine (Cl2) is identified as the limiting reactant because there is not enough of it to react with all the available aluminum (Al).
💡Excess Reactant
An excess reactant is a substance that remains after a chemical reaction has completed because it is present in a greater amount than needed to react with the limiting reactant. In the context of the video, aluminum is the excess reactant, as there is more aluminum available than what is required to react with the available chlorine.
💡Molar Mass
Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is used to convert between mass and the number of moles of a substance. In the video, molar masses of aluminum and chlorine are used to convert grams to moles, which is essential for determining the limiting reactant and calculating the amount of product formed.
💡Moles
Moles are a unit of measurement used in chemistry to express the amount of a substance. One mole contains Avogadro's number of entities (atoms, molecules, etc.). In the video, the number of moles is calculated for both aluminum and chlorine to compare their quantities and identify the limiting reactant.
💡Conversion Factor
A conversion factor is used to convert from one unit to another, often in scientific calculations. In chemistry, it can be used to convert between grams and moles using molar mass. The video script uses conversion factors to change the given mass of reactants into moles to facilitate the calculation of the limiting reactant.
💡Aluminum (Al)
Aluminum is a chemical element with the symbol Al and atomic number 13. In the video, aluminum is one of the reactants involved in the chemical reaction to form aluminum chloride (AlCl3). The amount of aluminum is compared with chlorine to determine the limiting reactant.
💡Chlorine (Cl2)
Chlorine is a chemical element with the symbol Cl and is diatomic in its standard state, meaning it naturally exists as Cl2. In the script, chlorine is identified as the limiting reactant in the reaction with aluminum to form aluminum chloride.
💡Aluminum Chloride (AlCl3)
Aluminum chloride is a chemical compound with the formula AlCl3. It is the product of the reaction between aluminum and chlorine. The video focuses on calculating the maximum amount of AlCl3 that can be produced given the amounts of aluminum and chlorine.
💡Chemical Equation
A chemical equation represents the substances involved in a chemical reaction and the ratios in which they react. In the video, the chemical equation is used to understand the stoichiometry of the reaction between aluminum and chlorine, which is essential for determining the limiting reactant and the amount of product formed.
💡Stoichiometry
Stoichiometry is the calculation of the quantitative relationships between reactants and products in a chemical reaction based on the law of conservation of mass. The video uses stoichiometry to determine the amounts of reactants needed to produce a certain amount of product and to identify the limiting reactant.
💡Grams to Moles Conversion
Converting grams to moles is a common procedure in chemistry to express the amount of substance in moles, which is necessary for stoichiometric calculations. The video script demonstrates this conversion for both aluminum and chlorine to find out how many moles of each reactant are available for the reaction.
Highlights

Introduction to an advanced chemistry practice problem involving limiting and excess reactants.

Equation provided for the reaction between aluminum (Al) and chlorine (Cl2) to form aluminum chloride (AlCl3).

Problem statement: Determine the maximum amount of AlCl3 that can be produced with given amounts of Al and Cl2.

Identification of the limiting reactant as the first step in solving the problem.

Conversion of grams to moles using the molar mass of aluminum and chlorine.

Calculation of moles of Al and Cl2 using their respective molar masses.

Determination of the limiting reactant by comparing the required moles of Cl2 to the available moles.

Understanding that the first reactant to be completely consumed is the limiting reactant.

Calculation of the moles of AlCl3 that can be produced using the limiting reactant (Cl2).

Conversion of moles of AlCl3 to grams using the molar mass of AlCl3.

Identification of the excess reactant and the calculation of the remaining amount.

Explanation of how the excess reactant (Aluminum) is determined and the calculation of its leftover moles.

Conversion of the remaining moles of aluminum to grams to find the excess amount.

Summary of the process to solve limiting reactant problems, emphasizing the importance of using moles.

Final answer: The greatest amount of AlCl3 that can be made and the amount of excess aluminum left over.

Emphasis on the practical application of the limiting reactant concept in chemical reactions.

Transcripts

Browse More Related Video

Limiting reactant example problem 1 | Chemistry | Khan Academy

Stoichiometry: Limiting Reactant, Left Over Excess Reactant, Percent Yield | Study Chemistry With Us

Stoichiometry - Limiting & Excess Reactant, Theoretical & Percent Yield - Chemistry

Limiting Reactant Practice Problem

Introduction to Limiting Reactant and Excess Reactant

4.61 | What is the limiting reactant in a reaction that produces sodium chloride from 8 g of sodium

Rate This

5.0 / 5 (0 votes)

Thanks for rating:

Related Tags
ChemistryLimiting ReactantProblem SolvingAluminumChlorineAlCl3Molar MassMole ConversionChemical ReactionEducationalSTEM