L'Hôpital's rule example 3 | Derivative applications | Differential Calculus | Khan Academy
TLDRThe video script presents a step-by-step mathematical approach to finding the limit of a function as x approaches 1. Initially, plugging in the value of 1 results in an undefined form, prompting the use of algebraic manipulation to create an l'Hopital's rule scenario. Through a series of derivative calculations, the limit is eventually determined to be 1/2, showcasing the power of l'Hopital's rule in resolving complex limits.
Takeaways
- 💡 The initial expression evaluated at x=1 results in an undefined form, not suitable for L'Hopital's rule.
- 💥 By algebraically adding the two expressions, a common denominator is formed, enabling further simplification.
- 💬 When the expressions are added and simplified, it results in an indeterminate form 0/0, making L'Hopital's rule applicable.
- 🔮 Applying L'Hopital's rule involves taking derivatives of the numerator and denominator and evaluating the limit again.
- 📚 The product rule is used for differentiation when the numerator's terms are products of functions.
- 📈 Simplification after differentiation is crucial for easier evaluation of the limit.
- 📌 The limit evaluation post-simplification might still result in an indeterminate form, necessitating the reapplication of L'Hopital's rule.
- 📝 Continual application of L'Hopital's rule and simplification leads to resolving the indeterminate form.
- 📡 The final evaluation after repeated application of L'Hopital's rule yields a concrete limit value.
- 📖 The process demonstrates the power of algebraic manipulation and L'Hopital's rule in solving complex limit problems.
Q & A
What is the initial expression the transcript is trying to evaluate at x approaches 1?
-The initial expression is the limit as x approaches 1 of x/(x-1) - 1/natural log(x).
Why is the direct substitution of x=1 not possible for the given expression?
-Direct substitution of x=1 is not possible because it results in an undefined form of 1/0 - 1/0, which is not an indeterminate form that can be resolved using l'Hopital's rule.
What is the significance of the natural log of 1 in the evaluation of the expression?
-The natural log of 1 is significant because it equals 0. This simplifies the expression when x=1 is substituted, as all terms involving natural log(1) become 0.
How does the transcript suggest we can manipulate the original expression to make it suitable for l'Hopital's rule?
-The transcript suggests that by adding the original expression to itself, we can create a common denominator and then simplify to get an expression that, when x approaches 1, results in an indeterminate form of 0/0 suitable for l'Hopital's rule.
What is the first step in applying l'Hopital's rule to the manipulated expression?
-The first step is to find the derivatives of the numerator and the denominator. The limit as x approaches 1 of the expression is then equal to the limit of the ratio of these derivatives.
What is the result of the first application of l'Hopital's rule?
-The first application of l'Hopital's rule results in a new indeterminate form of 0/0, which requires a second application of the rule to resolve.
How does the second application of l'Hopital's rule lead to a determinate result?
-The second application of l'Hopital's rule simplifies the expression to a form where the numerator evaluates to 1 and the denominator evaluates to 1/2 when x approaches 1, leading to a determinate result of 1/2.
What is the final answer for the limit as x approaches 1 of the original expression?
-The final answer for the limit as x approaches 1 of the original expression is 1/2.
What mathematical concept is used to resolve the undefined form 1/0 - 1/0?
-The mathematical concept used to resolve the undefined form 1/0 - 1/0 is l'Hopital's rule, which allows for the evaluation of limits of indeterminate forms by taking the derivatives of the numerator and the denominator.
What is the role of algebraic manipulation in solving this problem?
-Algebraic manipulation plays a crucial role in this problem by transforming the original expression into a form that can be analyzed using l'Hopital's rule, which would not have been possible without the manipulation.
Outlines
📚 Limit Calculation and L'Hopital's Rule
The paragraph discusses the process of finding the limit of a given expression as x approaches 1. Initially, plugging in the value of x results in an undefined form, which does not fit the criteria for L'Hopital's rule. However, by algebraically manipulating the expression and combining terms, the speaker creates a form that does fit the rule's criteria. The speaker then applies L'Hopital's rule by taking the derivatives of the numerator and the denominator and evaluates the limit, resulting in an indeterminate form. The process is repeated until a final answer is reached.
🔢 Application of L'Hopital's Rule for Indeterminate Forms
This paragraph continues the discussion on limit calculation, focusing on the application of L'Hopital's rule for indeterminate forms. The speaker evaluates the limit as x approaches 1 for a transformed expression, which initially results in another indeterminate form. By applying L'Hopital's rule again, taking the derivatives of both the numerator and the denominator, the speaker simplifies the expression to a determinate form. The final calculation yields a result of 1/2, demonstrating the effectiveness of L'Hopital's rule in resolving complex limit problems.
Mindmap
Keywords
💡limit
💡undefined
💡l'Hopital's rule
💡natural log
💡algebraic manipulation
💡indeterminate form
💡product rule
💡derivative
💡simplify
💡cancel out
💡evaluation
Highlights
The problem involves finding the limit of a function as x approaches 1.
The initial attempt to evaluate the expression at x=1 results in an undefined form, 1/0 - 1/0.
The undefined form does not fit the criteria for l'Hopital's rule, which requires 0/0 or ∞/∞.
The speaker suggests not giving up and looking for a way to manipulate the expression to apply l'Hopital's rule.
By adding the two expressions, a common denominator is formed, which could potentially lead to the l'Hopital indeterminate form.
The algebraic manipulation results in a new expression that is equivalent to the original, but with a different form.
Upon evaluating the new expression at x=1, an indeterminate form of 0/0 is obtained, which is suitable for l'Hopital's rule.
The first derivative of the numerator is calculated using the product rule.
The derivative of the denominator is found by differentiating each term separately.
After simplifying, the expression can be rewritten in a form that is ready for the second application of l'Hopital's rule.
The second application of l'Hopital's rule leads to a simpler expression with a clear limit.
The final result of the limit, after applying l'Hopital's rule twice, is 1/2.
The process demonstrates the utility of algebraic manipulation in solving limits that do not initially present as indeterminate forms suitable for l'Hopital's rule.
The method showcases the importance of recognizing when to apply l'Hopital's rule and how to transform expressions to meet the criteria.
The example serves as a lesson in problem-solving, emphasizing persistence and creativity in mathematical analysis.
The transcript provides a step-by-step guide that can be followed for similar limit problems.
The approach taken can be generalized to a variety of limit problems, making it a valuable strategy in calculus.
Transcripts
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