Worked example: cosine function from power series | Series | AP Calculus BC | Khan Academy
TLDRIn this educational video, the presenter tackles the evaluation of an infinite power series with a peculiar twist: the series involves powers of x to the sixth multiplied by a trigonometric hint, pi over two. The presenter encourages viewers to pause and attempt the problem, hinting at the Maclaurin Series for cosine as a potential solution. Through a step-by-step expansion of the series and a clever substitution of x with x to the third, the presenter reveals that the series is, in fact, the cosine of x cubed. The final evaluation of the series at x as the cube root of pi over two results in a surprising and satisfying conclusion: the series sums to zero.
Takeaways
- π The problem involves evaluating an infinite series with a specific power of x.
- π The series is expressed as the sum from n=0 to infinity of (-1)^n * x^(6n) / (2n)!.
- π€ The challenge is to determine what function this power series represents.
- π The hint suggests that the series might be related to a trigonometric function, given the presence of pi/2.
- π The series is expanded to show its terms, revealing a pattern similar to the Maclaurin series for cosine.
- 𧩠The series can be manipulated by replacing x with x^(1/3) to match the form of the cosine series.
- π This manipulation leads to the series representing the cosine of x^(1/3).
- π The goal is to evaluate the series when x equals the cubed root of pi/2.
- π― By substituting x with the cubed root of pi/2, the series simplifies to the cosine of pi/2.
- π The final evaluation shows that the cosine of pi/2 is zero, concluding the problem.
Q & A
What is the goal of the video?
-The goal of the video is to evaluate the given power series when x is equal to the cubed root of pi over two.
What is the hint provided in the video for solving the problem?
-The hint is to figure out what function the power series represents and then use that function to evaluate the series. Additionally, the number pi over two suggests using a trigonometric function.
What is the power series given in the video?
-The power series is the sum from n equals zero to infinity of (-1)^n * x^(6n) / (2^n * n!).
What is the expansion of the power series for the first few terms?
-The expansion starts with 1 (when n=0), then -x^6 / 2! (when n=1), +x^12 / 4! (when n=2), and -x^18 / 6! (when n=3), continuing in this pattern.
What trigonometric function does the power series resemble?
-The power series resembles the Maclaurin series for the cosine function.
What is the Maclaurin series for cosine of x?
-The Maclaurin series for cosine of x is approximately equal to 1 - x^2 / 2! + x^4 / 4! - x^6 / 6! and continues with alternating signs and increasing powers of x.
How can the power series be related to the cosine function?
-By replacing x with x^(1/3) in the cosine function, the power series matches the given series, indicating that the series is the Maclaurin series for cos(x^(1/3)).
What is the significance of the number pi over two in the context of the problem?
-The number pi over two is used to evaluate the power series when x is the cubed root of pi over two, which simplifies the evaluation process.
How does taking the cube of the cubed root of pi over two simplify the problem?
-Taking the cube of the cubed root of pi over two results in pi over two, which is a known value for the cosine function, making the evaluation straightforward.
What is the final evaluation of the power series when x is the cubed root of pi over two?
-The final evaluation is cos(pi/2), which is equal to zero.
Outlines
π Evaluating an Infinite Power Series
The speaker introduces an infinite power series involving a complex exponential term and aims to evaluate it when x equals the cubed root of pi over two. They encourage the audience to try solving it before revealing the method. The series is expanded to show its terms and compared to the Maclaurin series for cosine, suggesting a trigonometric function might be involved. The hint given is to identify the function represented by the series and then use that to evaluate it, with a particular focus on the 'suspicious' number pi over two, which might be related to a trigonometric evaluation.
𧩠Connecting the Series to Cosine Function
The speaker identifies the power series as being closely related to the Maclaurin series for the cosine function, with the exponents of x needing adjustment to match. They propose replacing x with x to the power of 1/3 to align with the cosine series, leading to the series representing the cosine of x cubed. The evaluation of the series when x is the cubed root of pi over two simplifies to the cosine of pi over two, which is zero. This clever manipulation of the series and the use of trigonometric identities provide a straightforward solution to the problem.
Mindmap
Keywords
π‘Infinite Series
π‘Power Series
π‘Cubed Root
π‘Factorial
π‘Trigonometric Function
π‘Maclaurin Series
π‘Cosine Function
π‘Exponents
π‘Evaluation
π‘Zero
Highlights
The presenter introduces an infinite series to be evaluated for a specific value of x.
The series involves powers of -1, x to the sixth power, and factorials in the denominator.
The goal is to evaluate the series when x equals the cubed root of pi over two.
The audience is encouraged to pause and attempt the problem independently.
A hint is given to determine the function that the power series represents.
The number pi over two is highlighted as a clue for potential trigonometric function usage.
The presenter expands the power series to get a better understanding of its structure.
The expansion reveals a pattern similar to the Maclaurin series for cosine.
The series is compared to the cosine Maclaurin series term by term.
A realization is made that the series could represent cosine of x cubed.
The presenter suggests replacing x with x to the third power to match the cosine series.
The series is rewritten as the cosine of x to the third power.
The evaluation of the series at the cubed root of pi over two is discussed.
The cube of the cubed root is calculated, simplifying the trigonometric function.
The final evaluation results in the cosine of pi over two, which is zero.
The problem is concluded with a clear and concise solution.
Transcripts
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