Use the Angle of Elevation to Find the Distance Between Two flying airplanes | Step-by-Step Tutorial
TLDRThis tutorial video explores a trigonometry word problem involving two airplanes flying at different heights. The challenge is to find the vertical distance between them given the angles of elevation from a ground point. Using trigonometric ratios, specifically the tangent function, the presenter sets up two equations based on the given angles (45 and 60 degrees) and solves for the unknown height 'h'. The final answer reveals a vertical distance of 1690.6 meters between the planes, offering viewers a clear application of trigonometry in real-world scenarios.
Takeaways
- π The video is a pre-math tutorial focusing on the applications of trigonometry with a word problem involving two airplanes.
- π« The scenario involves an airplane flying at a height of 4,000 meters above the ground, passing vertically above another airplane.
- π The angles of elevation from a point on the ground to each airplane are 60 degrees and 45 degrees, respectively.
- π The objective is to find the vertical distance between the two airplanes.
- π The problem introduces the concept of using trigonometric ratios, specifically the tangent function, to solve for the unknown distance.
- π The tangent of an angle is defined as the ratio of the opposite side to the adjacent side in a right triangle.
- βοΈ The script breaks down the problem into two right triangles, one smaller (triangle CDA) and one larger (triangle BDA), each with a different angle and side lengths.
- π For triangle CDA with a 45-degree angle, the tangent is equal to 1, leading to the equation \( x = 4000 - h \).
- π For triangle BDA with a 60-degree angle, the tangent is the square root of 3, resulting in the equation \( x = \frac{4000}{\sqrt{3}} \).
- π By comparing the two equations, the script derives a relationship between the height \( h \) and the distance \( x \).
- π The final step involves solving for \( h \) using the derived equation, which simplifies to \( h = 4000 - \frac{4000}{1.732} \).
- π― The calculated vertical distance between the two airplanes is approximately 1690.6 meters.
Q & A
What is the main topic of the video tutorial?
-The main topic of the video tutorial is the application of trigonometry in solving a word problem involving the vertical distance between two airplanes flying at different heights.
What is the height of the top airplane from the ground?
-The top airplane is flying at a height of 4,000 meters from the ground.
What are the angles of elevation from the ground to the two airplanes?
-The angles of elevation from the ground to the two airplanes are 60 degrees and 45 degrees, respectively.
What trigonometric ratio is used to solve the problem involving the smaller triangle (CDA)?
-The tangent ratio, which is the ratio of the opposite side to the adjacent side, is used to solve the problem involving the smaller triangle (CDA).
What is the value of the tangent of a 45-degree angle?
-The value of the tangent of a 45-degree angle is 1.
How is the equation for the smaller triangle (CDA) set up using the tangent ratio?
-The equation is set up as 1 (tangent of 45 degrees) equals (4,000 - h) divided by x, where x is the adjacent side and h is the unknown vertical distance between the two airplanes.
Which trigonometric ratio is used for the larger triangle (BDA)?
-The tangent ratio is also used for the larger triangle (BDA), with the angle being 60 degrees.
What is the value of the tangent of a 60-degree angle?
-The value of the tangent of a 60-degree angle is the square root of 3.
How is the equation for the larger triangle (BDA) derived?
-The equation is derived by setting the tangent of 60 degrees equal to the opposite side (4,000 meters) divided by the adjacent side (x), resulting in the equation β3 * x = 4,000.
What is the final step to find the vertical distance (h) between the two airplanes?
-The final step is to compare the two equations derived from the tangent ratios, isolate h, and solve for its value.
What is the calculated vertical distance (h) between the two airplanes?
-The calculated vertical distance (h) between the two airplanes is 1690.6 meters.
What is the significance of using trigonometry in this word problem?
-Trigonometry is significant in this word problem as it provides a mathematical method to determine the unknown vertical distance between two points when the angles and one side of the triangles are known.
Outlines
π Introduction to Trigonometry Application in Airplane Height Problem
This paragraph introduces a trigonometry word problem involving two airplanes flying at different heights. The problem requires finding the vertical distance between the two planes when one is at a constant height of 4,000 meters and the angles of elevation from a ground point to each plane are 60 degrees and 45 degrees respectively. A visual representation is provided to help understand the setup, and the focus is on using the tangent trigonometric ratio to solve for the unknown vertical distance 'h'.
π Detailed Solution Process for Airplane Height Problem
The second paragraph delves into the solution process for the trigonometry word problem. It begins by setting up two equations based on the tangent ratios for the angles given (45 and 60 degrees) and the known height difference (4,000 meters). The equations are derived by considering the smaller right triangle formed by the ground point and the lower airplane, and the larger triangle involving the upper airplane. The solution involves isolating the variable 'x', which represents the horizontal distance from the ground point to the lower airplane, and then using it to find 'h', the vertical distance between the two airplanes. The final step involves comparing the two equations, solving for 'h', and providing the numerical answer, which is approximately 1,690.6 meters. The paragraph concludes with the final answer and an invitation to subscribe for more educational content.
Mindmap
Keywords
π‘Trigonometry
π‘Word Problem
π‘Elevation
π‘Tangent
π‘Right Triangle
π‘Adjacent Side
π‘Opposite Side
π‘Angle of 45 Degrees
π‘Angle of 60 Degrees
π‘Cross Multiply
π‘Final Answer
Highlights
Introduction to the application of trigonometry in a word problem involving two airplanes and their relative positions.
Description of the problem setup with one airplane flying at 4,000 meters above the ground and passing vertically above another.
Identification of the angles of elevation from a point on the ground to the two airplanes as 60 degrees and 45 degrees.
Introduction of the goal to find the vertical distance between the two airplanes.
Visual representation of the problem with a vertical depiction of the two airplanes and the ground.
Explanation of the distance between the two planes denoted as 'h'.
Introduction of the smaller right triangle CDA and its sides' relationship to the trigonometric ratios.
Use of the tangent trigonometric ratio to relate the angle of 45 degrees to the sides of triangle CDA.
Calculation of the tangent of 45 degrees as 1, leading to the equation 1 = (4000 - h) / x.
Derivation of the first equation (Equation 1) to find the value of 'x'.
Shifting focus to the larger triangle B DA and its tangent ratio.
Application of the tangent of 60 degrees to the sides of triangle B DA.
Derivation of the second equation (Equation 2) using the tangent of 60 degrees.
Comparison of the two derived equations to solve for 'h'.
Isolation of 'h' and simplification of the equation to find the vertical distance.
Final calculation of 'h' using the approximation of the square root of 3 as 1.732.
Conclusion with the final answer of 1690.6 meters as the vertical distance between the two airplanes.
Encouragement for viewers to subscribe for more educational content.
Transcripts
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