4.80 | What is the concentration of NaCl in a solution if titration of 15.00 mL of the solution with

The Glaser Tutoring Company
23 Feb 202208:37
EducationalLearning
32 Likes 10 Comments

TLDRThe video script explains a titration process involving sodium chloride (NaCl) and silver nitrate (AgNO3). It demonstrates how to calculate the concentration of NaCl in a solution using stoichiometry and the balanced chemical equation. The process involves converting volumes from milliliters to liters, calculating moles, and using the molarity formula to find the concentration of NaCl.

Takeaways
  • πŸ§ͺ The task involves determining the concentration of sodium chloride (NaCl) in a solution using titration with silver nitrate (AgNO3).
  • πŸ” The balanced chemical equation for the reaction between NaCl and AgNO3 is given, resulting in the formation of silver chloride (AgCl) and sodium nitrate (NaNO3).
  • βš–οΈ The molarity of the silver nitrate solution is provided as 0.2503 M, and 20.22 mL of this solution is required to reach the endpoint in the titration.
  • πŸ“ The volume of the NaCl solution used in the titration is 15 mL, and the goal is to find the molarity of NaCl.
  • πŸ”’ The molarity formula, moles = molarity Γ— liters, is used to calculate the moles of AgNO3 from the given molarity and volume.
  • 🌑 The conversion from mL to liters is necessary, which is done by dividing the volume in mL by 1000.
  • πŸ“ Stoichiometry is applied to relate the moles of AgNO3 to the moles of NaCl, using the balanced chemical equation.
  • πŸ”„ Since the balanced equation shows a 1:1 ratio between AgNO3 and NaCl, the moles of NaCl are equal to the moles of AgNO3 used.
  • πŸ“‰ The molarity of NaCl is then calculated using the moles of NaCl and the volume of the NaCl solution in liters.
  • πŸ“ The final calculation results in a molarity of 0.3374 M for NaCl, rounded to four significant figures.
  • πŸ‘ The video script provides a step-by-step guide on how to perform the titration calculation, emphasizing the importance of using the balanced equation and molarity formula.
Q & A

  • What is the purpose of the titration process described in the script?

    -The purpose of the titration process is to determine the concentration of sodium chloride (NaCl) in a solution by reacting it with silver nitrate (AgNO3).

  • What is the balanced chemical equation for the reaction between silver nitrate and sodium chloride?

    -The balanced chemical equation is AgNO3 + NaCl β†’ AgCl + NaNO3. This indicates that one mole of silver nitrate reacts with one mole of sodium chloride to form one mole of silver chloride and one mole of sodium nitrate.

  • What is the molarity of the silver nitrate solution used in the titration?

    -The molarity of the silver nitrate solution is 0.2503 M.

  • How many milliliters of silver nitrate solution were used to reach the endpoint in the titration?

    -20.22 milliliters of the silver nitrate solution were used to reach the endpoint.

  • How many milliliters of the sodium chloride solution were titrated?

    -15 milliliters of the sodium chloride solution were titrated.

  • What formula is used to calculate the molarity of a solution?

    -The molarity formula is Molarity (M) = moles of solute / liters of solution.

  • How is the volume in milliliters converted to liters for the calculation of molarity?

    -To convert milliliters to liters, you divide the volume in milliliters by 1000 or move the decimal point three places to the left.

  • What is the relationship between the moles of AgNO3 and NaCl in the balanced equation?

    -In the balanced equation, the moles of AgNO3 and NaCl are in a 1:1 ratio, meaning one mole of AgNO3 reacts with one mole of NaCl.

  • How many moles of AgNO3 were used in the titration based on the given data?

    -The moles of AgNO3 used were 0.2503 M * 0.02022 L, which equals approximately 5.061 * 10^-3 moles.

  • What is the calculated molarity of the sodium chloride solution?

    -The calculated molarity of the sodium chloride solution is approximately 0.3374 M, based on the stoichiometry and the given volumes and molarity of the AgNO3 solution.

  • What is the significance of using stoichiometry in this titration problem?

    -Stoichiometry is used to relate the moles of one compound to another in a balanced chemical equation, allowing for the calculation of unknown concentrations based on known volumes and molarities.

Outlines
00:00
πŸ”¬ Understanding Titration in Sodium Chloride Solution

This paragraph discusses the concentration of sodium chloride (NaCl) in a solution determined by titration. It involves 15 mL of the solution titrated with 0.2503 M silver nitrate (AgNO3), requiring 20.22 mL to reach the endpoint. The reaction equation is provided, showing silver nitrate reacting with sodium chloride to form silver chloride (AgCl) and sodium nitrate (NaNO3). The equation is balanced without coefficients. The task is to find the concentration of NaCl using stoichiometry and the molarity formula. Detailed steps are provided, including converting volumes to liters and using molarity to find moles.

05:02
πŸ”„ Converting Moles to Determine Sodium Chloride Concentration

The focus here is on converting the moles of one compound (AgNO3) to another (NaCl) using the balanced equation. A ratio from the balanced equation shows a 1:1 mole relationship between AgNO3 and NaCl. The moles of AgNO3 calculated previously are converted to moles of NaCl. To find the molarity of NaCl, the volume in liters is used. The calculation yields the molarity of NaCl as 0.3374 M, with the process emphasized on using the molarity formula twice and converting units appropriately. The video concludes with encouraging words and a thank you.

Mindmap
Keywords
πŸ’‘Concentration
Concentration in the context of the video refers to the amount of a particular substance, in this case, sodium chloride (NaCl), present in a given volume of solution. It is a key concept because the video's main theme is to determine the molarity of NaCl. The script mentions 'concentration of sodium chloride' and uses the term in the context of titration to find the molarity.
πŸ’‘Sodium Chloride (NaCl)
Sodium chloride, known as NaCl, is a common salt compound that the video aims to determine the concentration of in a solution. It is central to the video's theme as the substance being analyzed through titration. The script mentions it in the context of finding its molarity in a solution.
πŸ’‘Titration
Titration is a laboratory technique used to determine the concentration of an unknown solution by reacting it with a solution of known concentration. In the video, titration is used to find the molarity of NaCl by reacting it with silver nitrate (AgNO3), which is a key step in solving the problem presented.
πŸ’‘Molarity
Molarity is defined as the number of moles of solute per liter of solution. It is the main unit of concentration that the video seeks to calculate for NaCl. The script refers to molarity multiple times, emphasizing its importance in the context of the titration process.
πŸ’‘Silver Nitrate (AgNO3)
Silver nitrate is a chemical compound used in the video as the titrant, which is the solution of known concentration used in titration. The script mentions '0.2503 molarity silver nitrate' and explains how it is used to determine the concentration of NaCl.
πŸ’‘Stoichiometry
Stoichiometry is the calculation of relative quantities of reactants and products in chemical reactions. The video uses stoichiometry to relate the moles of AgNO3 to the moles of NaCl, as the balanced chemical equation shows a one-to-one ratio between them.
πŸ’‘Balanced Equation
A balanced chemical equation is one where the number of atoms of each element is the same on both sides of the equation. The video script refers to the balanced equation of AgNO3 reacting with NaCl to form AgCl and NaNO3, which is crucial for understanding the stoichiometric relationship between the reactants.
πŸ’‘Moles
The term 'moles' refers to the amount of a substance, measured in terms of the number of atoms or molecules it contains. In the video, moles are calculated to relate the known amount of AgNO3 to the unknown amount of NaCl using the balanced equation.
πŸ’‘Mils
Mils is a unit of volume used in the video to measure the volume of solutions in the titration process. The script converts mils to liters, which is necessary for calculating molarity, demonstrating the importance of unit conversion in chemical calculations.
πŸ’‘Endpoint
The endpoint in titration is the point at which the reaction between the titrant and the analyte is complete. The video script mentions reaching the endpoint with '20.22 mils of the silver nitrate solution,' indicating the completion of the titration process.
πŸ’‘Unit Conversion
Unit conversion is the process of changing a physical quantity from one unit to another. The video script includes converting mils to liters, which is essential for calculating molarity and understanding the concentration of the NaCl solution.
Highlights

The concentration of sodium chloride (NaCl) in a solution is being determined through titration.

15 mL of the solution is titrated with 0.2503 molarity silver nitrate (AgNO3).

20.22 mL of silver nitrate solution is required to reach the endpoint.

The balanced chemical equation for the reaction is AgNO3 + NaCl β†’ AgCl + NaNO3.

The balanced equation indicates a 1:1 molar ratio between AgNO3 and NaCl.

The molarity formula is used to calculate moles: moles = molarity Γ— liters.

Conversion from mL to liters is necessary, dividing by 1000.

Moles of AgNO3 are calculated as 0.2503 molarity times 0.02022 liters.

The moles of AgNO3 are found to be approximately 5.061 Γ— 10^-3 moles.

Using stoichiometry, the moles of NaCl are determined to be equal to the moles of AgNO3.

The molarity of NaCl is then calculated using the moles of NaCl and the volume in liters.

15 mL of NaCl solution is converted to 0.015 liters.

The molarity of NaCl is calculated to be 0.3 molarity.

The significance of using the balanced equation in stoichiometry is emphasized.

The practical application of molarity formula in titration is demonstrated.

The importance of converting units from mL to liters in chemical calculations is highlighted.

The process concludes with the final molarity of NaCl being determined as 0.3 molarity.

Transcripts

Browse More Related Video

Molarity Practice Problems

4.81 | In a common medical laboratory determination of the concentration of free chloride ion in

4.93 | How many milliliters of a 0.1500-M solution of KOH will be required to titrate 40.00 mL of a

How to Do Solution Stoichiometry Using Molarity as a Conversion Factor | How to Pass Chemistry

Chapter 7: Before Equivalence Point | CHM 214 | 067

Ion Concentration in Solutions From Molarity, Chemistry Practice Problems

Rate This

5.0 / 5 (0 votes)

Thanks for rating:

Related Tags
ChemistryTitrationMolaritySodium ChlorideSilver NitrateStoichiometryMoles CalculationEducationalScience TutorialLab TechniquesChemical Reaction