Example (2.2) - Finding the limit of a function #14 (Calc)
TLDRIn this educational video, the presenter demonstrates how to find the limit of a function as 'u' approaches 3. Initially, plugging in 3 results in a domain error due to division by zero. The solution involves factoring the numerator and denominator, breaking down the expression into simpler components. Through algebraic manipulation, the presenter simplifies the function, cancels out terms, and evaluates the limit, concluding with the result of 4. This process highlights the importance of factoring in solving limits and provides a clear example for students to follow.
Takeaways
- π The video is an educational example from a math textbook, specifically section 3.2, focusing on finding a limit as a variable approaches a certain value.
- π The limit to be found is as 'u' approaches 3 for the function \( A^u \) to the 4th minus 81 over \( u^3 \) minus 27.
- β Initially, plugging in 3 for 'u' results in a domain error because \( 3^3 \) minus 27 equals zero, making the denominator undefined.
- π The solution involves factoring the numerator and denominator to simplify the expression and avoid the domain error.
- π The numerator \( u^4 - 81 \) is factored into \( (u^2 + 9)(u^2 - 9) \), which further breaks down into \( (u+3)(u-3)(u^2+9) \).
- π The denominator \( u^3 - 27 \) is factored using the difference of cubes formula, resulting in \( (u-3)(u^2+3u+9) \).
- π After factoring, terms \( (u-3) \) in the numerator and denominator cancel each other out, simplifying the expression.
- 𧩠The simplified expression is \( (u^2 + 9)(u+3) \) over \( u^2 + 3u + 9 \).
- π’ Substituting 3 for 'u' in the simplified expression allows for the evaluation of the limit without any undefined terms.
- π The final calculation of the limit as 'u' approaches 3 results in the value 4, after simplifying the fraction \( \frac{18 \times 6}{27} \) to \( \frac{108}{27} \) and then further to \( \frac{36}{9} \).
- π― The key takeaway is that the limit of the given function as 'u' approaches 3 is 4, achieved through careful factoring and simplification.
Q & A
What is the mathematical problem being discussed in the script?
-The script discusses the process of finding the limit as 'u' approaches 3 for the function (u^4 - 81) / (u^3 - 27).
Why can't we directly substitute 3 into the function to find the limit?
-Direct substitution is not possible because when 'u' equals 3, the denominator (u^3 - 27) becomes zero, resulting in a domain error and making the function undefined.
What algebraic technique is used to simplify the function before finding the limit?
-The technique used is factoring. The numerator u^4 - 81 and the denominator u^3 - 27 are both factored to simplify the expression.
What is the factored form of u^4 - 81?
-The factored form of u^4 - 81 is (u^2 + 9)(u^2 - 9), which can further be broken down into (u^2 + 9)(u + 3)(u - 3).
How is the denominator u^3 - 27 factored?
-The denominator is factored using the formula for a^3 - b^3, which results in (u - 3)(u^2 + 3u + 9).
What happens when we cancel out the common factor (u - 3) from the numerator and denominator?
-After canceling out (u - 3), the expression simplifies to (u^2 + 9)(u + 3) / (u^2 + 3u + 9).
Why is it important to cancel out the common factor (u - 3)?
-Canceling out the common factor (u - 3) is important because it removes the undefined part of the function and allows us to evaluate the limit as 'u' approaches 3.
What is the simplified form of the function after canceling out (u - 3)?
-The simplified form of the function is u^2 + 9u + 9 / u^2 + 3u + 9.
How do we evaluate the limit as 'u' approaches 3 for the simplified function?
-By substituting 'u' with 3 in the simplified function and performing the arithmetic, we can find the limit.
What is the final result of the limit as 'u' approaches 3 for the given function?
-The final result of the limit as 'u' approaches 3 for the given function is 4.
What is the significance of the limit being 4 in the context of the script?
-The limit being 4 signifies the value that the function approaches as 'u' gets arbitrarily close to 3, which is a key concept in calculus.
Outlines
π Calculating the Limit of a Polynomial Function
This paragraph discusses the process of finding the limit of a polynomial function as 'u' approaches 3. The function given is 'u^4 - 81' over 'u^3 - 27'. Initially, the presenter tries to substitute 'u' with 3, but encounters a domain error due to the denominator becoming zero. To resolve this, the presenter factors the polynomials, using algebraic identities to simplify the expression. The 'u^4 - 81' is factored into '(u^2 + 9)(u^2 - 9)', and further into '(u + 3)(u - 3)(u^2 + 3u + 9)'. Similarly, 'u^3 - 27' is factored into '(u - 3)(u^2 + 3u + 9)'. After canceling out the common factor of 'u - 3', the function simplifies to 'u^2 + 9' over 'u^2 + 3u + 9'. The presenter then evaluates the limit by substituting 'u' with 3, resulting in a simplified expression that can be easily calculated.
π Final Evaluation of the Limit
In this paragraph, the presenter concludes the calculation of the limit. After simplifying the function to 'u^2 + 9' over 'u^2 + 3u + 9' and canceling out the common factors, the presenter substitutes 'u' with 3 to find the limit. The resulting expression is '3^2 + 9' over '3^2 + 3*3 + 9'. After performing the arithmetic, the presenter simplifies the fraction to '18*6' over '27', which further simplifies to '108' over '27'. The final step is to divide both the numerator and the denominator by 9, yielding the limit as '4'. The presenter confirms that the limit of the original function as 'u' approaches 3 is indeed 4.
Mindmap
Keywords
π‘Limit
π‘Factoring
π‘Domain Error
π‘Algebra 2
π‘Cube
π‘Difference of Cubes
π‘Factor Line
π‘Cancellation
π‘Evaluation
π‘Undefined
π‘Simplification
Highlights
Introduction to the problem of finding the limit as u approaches 3 for a given function.
Initial attempt to plug in the value 3 leads to a domain error, indicating the function is undefined at that point.
The necessity of factoring the numerator and denominator to simplify the expression.
Factoring the numerator u^4 - 81 into u^2 + 9u^2 - 9 using algebraic identities.
Explanation of the factoring process for u^4 - 81, highlighting the cancellation of terms.
Factoring the denominator u^3 - 27 using the formula for a^3 - b^3.
Breaking down the denominator into (u - 3)(u^2 + 3u + 9).
Further factoring of u^2 - 9 into (u + 3)(u - 3).
Cancellation of the common factor (u - 3) in the numerator and denominator.
Simplification of the expression to u^2 + 9(u + 3) / (u^2 + 3u + 9).
Evaluation of the limit by substituting u = 3 into the simplified expression.
Calculation of the limit, resulting in a simplified fraction of 18 * 6 over 27.
Further simplification of the fraction to 36 over 9.
Final evaluation of the limit as u approaches 3, which is 4.
Emphasis on the importance of factoring and simplification in evaluating limits.
Demonstration of the algebraic process and the steps taken to solve the limit problem.
Conclusion of the mathematical tutorial with the final answer and a summary of the method used.
Transcripts
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