Solving A Non-Linear Differential Equation

SyberMath
10 Mar 202408:13
EducationalLearning
32 Likes 10 Comments

TLDRIn this video, we solve a differential equation, starting with y' = 1 + 2/y - x. The presenter discusses two methods: the first involves common denominators and cross multiplication, while the second uses substitution to simplify the equation. By substituting u for y - x, the equation becomes separable, leading to a solution. The video also explains how to verify the solution and addresses linearity vs. nonlinearity in differential equations. Viewers are encouraged to comment with alternative methods and thoughts.

Takeaways
  • ๐Ÿ“š The video discusses solving a differential equation with the given equation y' = 1 + 2/y - x.
  • ๐Ÿ” Two different approaches to solving the equation are presented, with one method being potentially incomplete.
  • ๐Ÿ“‰ The first method involves creating a common denominator and cross-multiplication, but its usefulness is questioned.
  • ๐Ÿ“ˆ The second method utilizes a substitution technique, introducing a new variable U to simplify the equation.
  • ๐Ÿ”‘ The substitution sets y - x = U, which transforms the equation into a system that can be differentiated.
  • ๐Ÿงฉ The differentiation leads to an equation involving U', the derivative of U with respect to x.
  • ๐Ÿ”„ A separable differential equation is formed, allowing for the separation of variables and integration.
  • ๐Ÿ“ The integration results in U^2 / 2 = 4x + K, which is then manipulated to solve for U.
  • ๐Ÿ”ฎ Back-substitution is used to express the solution in terms of the original variable y, resulting in y = x ยฑ sqrt(4x + K).
  • ๐Ÿ”ง The solution is tested by differentiating it and comparing it to the original differential equation to verify its correctness.
  • ๐Ÿ‘ The video concludes with the verification that the derived solution satisfies the original problem, emphasizing the importance of checking solutions.
Q & A
  • What is the differential equation given in the video?

    -The differential equation given in the video is y' = 1 + 2/y - x.

  • What are the two approaches presented in the video to solve the differential equation?

    -The two approaches presented are: 1) Making a common denominator and attempting to solve for y - x, and 2) Using a substitution method with y - x = u.

  • Why is the first approach not complete according to the video?

    -The first approach is not complete because after making a common denominator and cross-multiplying, the presenter does not follow through with a solution for y - x.

  • What is the substitution used in the second approach to simplify the equation?

    -In the second approach, the substitution used is y - x = u, which simplifies the equation to y' = 1 + 2/u.

  • How does the video determine if the given differential equation is linear or nonlinear?

    -The video determines that the equation is nonlinear because y' is multiplied by itself (y' * y'), which is not a characteristic of linear equations.

  • What is the derivative of u with respect to x (u') in terms of y' and x?

    -The derivative of u with respect to x (u') is given by y' - 1, as shown when the presenter differentiates both sides of y - x = u.

  • How does the video simplify the equation to a separable differential equation?

    -The video simplifies the equation by replacing y' with u' + 1 and then isolating u' to get u' = 2/u, which is a separable differential equation.

  • What is the integral form of the separable differential equation derived in the video?

    -The integral form is derived as โˆซu du = โˆซ2 dx, which simplifies to u^2/2 = 2x + C after integration.

  • How does the video back-substitute to find the solution for y in terms of x?

    -The video back-substitutes by replacing u with y - x and then solving for y, resulting in y = x ยฑ โˆš(4x + k), where k is a constant.

  • What method does the video use to verify the solution?

    -The video verifies the solution by differentiating the proposed solution for y and checking if it equals the original differential equation y' = 1 + 2/y - x.

  • What does the video suggest for viewers who have alternative methods to solve the equation?

    -The video suggests that viewers who have alternative methods to solve the equation should share them in the comment section.

Outlines
00:00
๐Ÿ” Introduction to Solving a Differential Equation

The video begins with an introduction to solving a differential equation, specifically one where y' = 1 + 2/y - x. Two methods for solving the equation are mentioned, with a hint that one might not be fully completed. The first approach involves creating a common denominator and considering the linearity of the equation. It is clarified that the given equation is nonlinear, which generally makes it more challenging to solve. The presenter invites viewers to share methods for solving such equations in the comments section and then proceeds to the second method, which involves a substitution technique to keep y and x together in the form of y - x.

05:03
๐Ÿ“š Using Substitution to Solve the Differential Equation

The second method focuses on the power of substitution in solving differential equations. The presenter chooses to use the variable U as a substitute for y - x, turning the equation into a system that can be differentiated. By differentiating both sides of y - x = U, the presenter eliminates y' from the equation, expressing it in terms of U and x. The resulting equation U' = 2/U is identified as a separable differential equation, which can be solved by separating variables and integrating. After integrating, the solution is found to be U^2 / 2 = 2x + C, which, upon back-substitution, gives y - x = 4x + K. The solution is then simplified to y = x ยฑ โˆš(4x + K), where K is a constant. The presenter also demonstrates the verification of the solution by differentiating the proposed solution and showing it equals the original equation. The video concludes with an invitation for viewers to test the solution and engage with the content through likes, comments, and subscriptions.

Mindmap
Keywords
๐Ÿ’กDifferential Equation
A differential equation is a mathematical equation that involves a function and its derivatives. In the video, the main theme revolves around solving a specific differential equation, which is a fundamental concept in calculus and mathematical analysis. The equation given is y' = 1 + 2/y - x, and the process of solving it forms the core of the video's educational content.
๐Ÿ’กCommon Denominator
A common denominator in mathematics is a single denominator that multiple fractions can share, allowing them to be added or subtracted. In the script, the presenter uses a common denominator to combine terms involving 'y' and 'x' in the differential equation, which is a step towards simplifying the equation and moving closer to a solution.
๐Ÿ’กCross Multiplication
Cross multiplication is a technique used in algebra to multiply each term in one fraction by each term in another fraction to eliminate the fractions. In the video, the presenter applies cross multiplication to the differential equation to transform it into a form that is easier to work with, specifically to isolate 'y - x'.
๐Ÿ’กLinearity
Linearity in the context of differential equations refers to equations where the unknown function and its derivatives are to the first power. The video discusses whether the given differential equation is linear or nonlinear. It is identified as nonlinear because of the presence of the term '2/y', which involves the derivative multiplied by the function itself.
๐Ÿ’กSubstitution
Substitution is a mathematical method used to simplify expressions or equations by replacing a complex expression with a simpler variable. In the video, the presenter introduces a substitution method by setting 'y - x' equal to a new variable 'U', which simplifies the process of solving the differential equation by keeping 'y' and 'x' together.
๐Ÿ’กSeparable Differential Equation
A separable differential equation is a type of differential equation where the variables can be separated on either side of the equation, making it easier to solve. The video demonstrates how the given differential equation can be transformed into a separable form, which is then solved by integrating both sides with respect to their respective variables.
๐Ÿ’กIntegration
Integration is a fundamental operation in calculus, which is the reverse process of differentiation. It is used to find the integral or the original function when given its derivative. In the video, integration is used to solve the separable differential equation after the variables have been separated.
๐Ÿ’กBack Substitution
Back substitution is the process of replacing the substituted variables with their original expressions to find the solution in the original variable's terms. After solving for 'U', the presenter uses back substitution to express the solution in terms of 'y' and 'x', which is crucial for verifying the solution to the original differential equation.
๐Ÿ’กVerification
Verification in mathematics is the process of confirming that a proposed solution to an equation or problem is correct. In the context of the video, the presenter verifies the solution by differentiating the proposed solution and showing that it satisfies the original differential equation, thus confirming its validity.
๐Ÿ’กImplicit Solution
An implicit solution is a form of expressing the solution to a differential equation where the variables are not explicitly isolated. In the video, the presenter acknowledges that sometimes the solution may be implicit, meaning 'y' and 'x' are intertwined, and it may not be possible to express 'y' solely in terms of 'x'.
๐Ÿ’กSquare Root
The square root operation is used to find a value that, when multiplied by itself, gives a specified number. In the video, the presenter uses the square root to express 'y' in terms of 'x' after back substitution, which involves taking the square root of '4x + K' to solve for 'y'.
Highlights

Introduction to solving a differential equation with y' = 1 + 2/y - x.

Presentation of two approaches to solving the equation, with a note on the potential incompleteness of one.

First approach involves creating a common denominator and cross-multiplication.

Discussion on the linearity of the equation, identifying it as nonlinear.

Mention of the difficulty in solving nonlinear equations and an invitation for alternative methods.

Introduction of the second method focusing on keeping y and x together in the form of y - x.

Use of substitution with a new variable U to simplify the equation.

Transformation of the equation into a system that can be differentiated.

Differentiation of both sides to eliminate y' and express everything in terms of U and x.

Identification of a separable differential equation and the process of separating variables.

Integration of both sides to solve for U in terms of x.

Back-substitution of U with y - x to find the solution for y.

Explanation of the process to isolate y and obtain the final solution.

Testing the solution by differentiating it and comparing it with the original equation.

Confirmation that the solution checks out and the process of verifying it.

Encouragement for viewers to find out if the other solution also checks out.

Conclusion of the video with a thank you message and an invitation to engage with the content.

Transcripts
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