π·11 - Gauss Jordan Elimination and Reduced Row Echelon Form
TLDRThis video script outlines the process of solving a system of linear equations using the Gauss-Jordan elimination method. It guides viewers through representing the equations as an augmented matrix and transforming it into reduced row echelon form. The method involves a series of elementary row operations to eliminate variables and isolate the leading diagonal. The script culminates in finding the values of the unknown variables x, y, and z, concluding with x = 1, y = 2, and z = 3.
Takeaways
- π Gauss-Jordan Elimination is a method used to solve systems of linear equations by transforming an augmented matrix into Reduced Row Echelon Form (RREF).
- π’ The process involves representing the system of equations as an augmented matrix with coefficients of the unknown variables (x, y, z) and constants.
- β The aim is to zero out elements in the matrix not on the leading diagonal and make the diagonal elements equal to 1 through elementary row operations.
- π Elementary row operations include adding or subtracting multiples of one row to another, and multiplying a row by a non-zero scalar.
- π― The first step is to eliminate the first variable (x) from the second and third equations to create a 'staircase' of zeros below the first pivot.
- π Further row operations are performed to eliminate the second variable (y) from the third equation, creating a further staircase of zeros.
- π When all off-diagonal elements above the pivot are zero, the matrix is ready to be transformed into RREF by making diagonal elements equal to 1.
- π This is done by dividing each pivot row by the leading diagonal element, normalizing them to 1.
- π By observing the resulting RREF, we can directly read the values of the variables (x, y, z) from the last column of the matrix.
- π The final solution to the system of equations is x = 1, y = 2, and z = 3, as deduced from the last column of the RREF matrix.
Q & A
What method is used in the video to solve the system of linear equations?
-The method used in the video to solve the system of linear equations is the Gauss-Jordan elimination method.
What are the unknown variables the video aims to find?
-The unknown variables the video aims to find are x, y, and z.
How is the system of linear equations represented initially in the Gauss-Jordan elimination method?
-The system of linear equations is represented initially as an augmented matrix, with the coefficients of the unknown variables x, y, z in the rows and the constants on the right-hand side of the equal sign.
What is the goal when transforming the augmented matrix using elementary row operations?
-The goal when transforming the augmented matrix using elementary row operations is to convert it into the reduced row echelon form, where all elements above the leading diagonal are zero and the elements in the leading diagonal are one.
How does the video demonstrate the process of eliminating variables from the system?
-The video demonstrates the process of eliminating variables by performing a series of elementary row operations, such as multiplying rows by constants, adding or subtracting rows from each other, to manipulate the matrix into the desired form.
What specific row operation does the video perform first to start the elimination process?
-The first specific row operation performed in the video is multiplying row three by three and then subtracting that from row two to make the first element of row two zero.
How does the video ensure that the elements in the leading diagonal become one?
-The video ensures that the elements in the leading diagonal become one by dividing each of the rows by the leading diagonal elements, after all other elements above the diagonal have been reduced to zero.
What are the final values of x, y, and z after completing the Gauss-Jordan elimination process?
-The final values of x, y, and z after completing the Gauss-Jordan elimination process are x = 1, y = 2, and z = 3.
What is the significance of the reduced row echelon form in solving systems of linear equations?
-The significance of the reduced row echelon form is that it simplifies the system of linear equations into a form where the solution can be easily read off from the matrix, with each variable corresponding to a pivot position in its respective row.
How does the Gauss-Jordan elimination method differ from other methods of solving systems of linear equations?
-The Gauss-Jordan elimination method differs from other methods as it involves transforming the augmented matrix into the reduced row echelon form, which not only solves the system but also provides a systematic way to deal with inconsistent or dependent systems of equations.
Outlines
π Introduction to Solving Systems of Linear Equations
This paragraph introduces the Gauss-Jordan elimination method for solving a system of linear equations. The goal is to find the unknown variables x, y, and z by representing the equations in the form of an augmented matrix. The initial step involves transforming the matrix into the reduced row echelon form through elementary row operations, aiming to achieve zeros in the non-leading diagonal and ones on the diagonal. The process begins with setting up the matrix according to the given equations and separating constants from the variables.
π’ Performing Elementary Row Operations
In this paragraph, the focus is on performing specific elementary row operations to simplify the augmented matrix. The operations include multiplying a row by a certain factor and then adding or subtracting it from another row. This process is used to manipulate the matrix in a way that zeros are created in specific positions. The detailed calculations and the resulting changes in the matrix are explained step by step, showing how the values evolve through each operation.
π― Achieving Zero Values and Finalizing the Matrix
This section describes the continued effort to achieve zero values in specific cells of the matrix through targeted row operations. The process involves a series of multiplications and additions/subtractions, with the aim of reaching a point where the leading diagonal elements are the only non-zero values. The explanation includes the rationale behind each operation and the resulting matrix configuration after each step.
π Conclusion and Solution of the System of Equations
The final paragraph concludes the Gauss-Jordan elimination process by making the final adjustments to the matrix to find the values of x, y, and z. The operations focus on adjusting the leading diagonal elements to one while maintaining the zeros in other positions. After completing the row operations, the values of the unknown variables are determined by observation. The solution is presented clearly, with z being equal to three, y equal to two, and x equal to one.
Mindmap
Keywords
π‘Gauss-Jordan Elimination
π‘Linear Equations
π‘Augmented Matrix
π‘Elementary Row Operations
π‘Reduced Row Echelon Form
π‘Unknown Variables
π‘Coefficients
π‘Constants
π‘Row Operations
π‘Leading Diagonal
π‘Solving Systems of Equations
Highlights
The video demonstrates solving a system of linear equations using the Gauss-Jordan elimination method.
The goal is to find the unknown variables x, y, and z from the given system of equations.
Linear equations are initially represented in the form of an augmented matrix, with coefficients of the variables and constants.
Elementary row operations are applied to transform the matrix into the reduced row echelon form.
The process involves making elements in the leading diagonal go to one and other elements to zero.
Row three is multiplied by three and subtracted from row two to eliminate the first element in row three.
Row three is further manipulated to make the element in the second position zero by multiplying and subtracting from row one.
Row two is modified by multiplying it by negative five to make the element in the second position match the leading diagonal element.
Row three is adjusted to have zero in the second position by multiplying row two by negative five and adding it to row three.
Row one is modified by multiplying row three by five and adding it to row one to make the second element zero.
Row two is adjusted by multiplying row three by two and adding it to row two to make the second element zero.
Row one is modified by multiplying row two by negative three and adding it to row one to make the second element zero.
The leading diagonal elements are normalized to one by dividing each row by its leading element.
The final values of x, y, and z are determined to be 1, 2, and 3, respectively.
The method provides a systematic approach to solving systems of linear equations with three variables.
Gauss-Jordan elimination is an effective technique for finding exact solutions to linear systems.
The process requires careful execution of row operations to maintain the integrity of the solution path.
Transcripts
Browse More Related Video
Gauss Jordan Elimination & Reduced Row Echelon Form
PreCalculus - Matrices & Matrix Applications (5 of 33) Method of Gaussian Elimination: Example
PreCalculus - Matrices & Matrix Applications (28 of 33) Solving Sys of Linear Eqn with Inverse
Gaussian Elimination With 4 Variables Using Elementary Row Operations With Matrices
7.3.3 Row Echelon Form of a Matrix
Matrices: Reduced row echelon form 2 | Vectors and spaces | Linear Algebra | Khan Academy
5.0 / 5 (0 votes)
Thanks for rating: