Proof: S (or entropy) is a valid state variable | Thermodynamics | Physics | Khan Academy
TLDRThis video explains the concept of state variables in thermodynamics, focusing on internal energy (U) and the limitations of using heat (Q) as a state variable. The instructor uses a Carnot cycle to illustrate how internal energy remains constant regardless of the process path. The video then introduces entropy (S) as a new state variable, defined by the heat added to the system divided by the temperature. Through mathematical derivation, it's shown that entropy remains constant over a complete cycle, validating it as a legitimate state variable.
Takeaways
- π State variables like internal energy (U) should have the same value when a system returns to its initial state, regardless of the path taken.
- π Heat is not a state variable because its value can change depending on the process, unlike internal energy.
- π The concept of 'heat content' as a state variable is flawed because it accumulates based on the path taken, not just the state.
- β»οΈ The Carnot cycle is used to illustrate the properties of state variables, showing that internal energy remains constant.
- π The net heat added to a system in a cycle equals the work done if the internal energy does not change.
- π The area inside a cycle on a PV diagram represents the work done by or on the system.
- π‘οΈ A new state variable 'S' is proposed, defined as the change in entropy, which is the heat added divided by the temperature at which it was added.
- π For 'S' to be a valid state variable, its change (delta S) around the Carnot cycle must be zero, indicating no change in entropy.
- π The integral of pressure times volume change (PdV) is used to calculate the work done during isothermal processes in a Carnot cycle.
- β« The integral of nRT/V from one volume to another on an isotherm simplifies to nRT times the natural logarithm of the volume ratio.
- π The change in entropy (delta S) for a Carnot cycle is shown to be zero, confirming entropy as a valid state variable, although its deeper meaning is yet to be explored.
Q & A
What is a state variable?
-A state variable is a property of a system that depends only on the current state of the system, not on the path taken to reach that state. In the script, internal energy (U) is given as an example of a state variable.
Why can't heat be considered a state variable?
-Heat cannot be considered a state variable because its value depends on the path taken by the system. For example, the change in heat content can vary depending on the process, even if the system returns to the same state.
What is the Carnot cycle and why is it significant in this context?
-The Carnot cycle is an idealized thermodynamic cycle that consists of two isothermal processes and two adiabatic processes. It is significant because it is used to illustrate the concept of state variables and to derive the relationship between heat transfer and work in an idealized engine.
What is the relationship between the net heat added to a system and the work done during a Carnot cycle?
-In a Carnot cycle, the net heat added to the system is equal to the work done by the system, since the internal energy does not change during the cycle.
How is work related to heat transfer in the context of the Carnot cycle?
-Work in the Carnot cycle can be represented as the area under the curve on a PV diagram during an isothermal process. The heat added to the system is equal to the work done by the system in the isothermal expansion from A to B.
What is the integral calculation for heat transfer (Q1) during an isothermal process in a Carnot cycle?
-The integral calculation for heat transfer (Q1) during an isothermal process in a Carnot cycle is the integral from the initial volume (VA) to the final volume (VB) of nRT/V dV, where n is the number of moles, R is the gas constant, T is the temperature, and V is the volume.
What is the significance of the state variable S introduced in the script?
-The state variable S, which is defined as the change in entropy, is significant because it is a legitimate state variable that remains constant during a Carnot cycle, unlike heat content which depends on the path.
How is the change in entropy (ΞS) calculated for a Carnot cycle?
-The change in entropy (ΞS) for a Carnot cycle is calculated as the sum of the heat added to the system (Q1) divided by the temperature at which it was added (T1), plus the heat removed from the system (Q2) divided by the temperature at which it was removed (T2).
What is the final result of the change in entropy (ΞS) for a complete Carnot cycle?
-The final result of the change in entropy (ΞS) for a complete Carnot cycle is zero, indicating that entropy is indeed a state variable and remains constant regardless of the path taken during the cycle.
What does the natural log of the ratio of volumes (VB/VA and VD/VC) equal to 1 imply in the context of the Carnot cycle?
-In the context of the Carnot cycle, the natural log of the ratio of volumes (VB/VA and VD/VC) equal to 1 implies that the change in entropy (ΞS) is zero, confirming that entropy is a state variable that does not change during a complete cycle.
Outlines
π Understanding State Variables and the Carnot Cycle
The paragraph introduces the concept of state variables, using internal energy (U) as an example. It explains that state variables, like U, should remain constant for a system returning to its initial state after a cycle, regardless of the path taken. The script contrasts this with heat, which is not a state variable due to its dependency on the process. The Carnot cycle is used to illustrate this, showing that the net heat added to a system during a cycle equals the work done, assuming no change in internal energy. The area inside the cycle on a PV diagram represents the work done, which is also the net heat added. The paragraph concludes by suggesting that a new state variable, related to heat, might be defined that remains constant over a cycle.
π§ Calculating Heat and Work in the Carnot Cycle
This paragraph delves into the specifics of calculating heat transfer (Q1 and Q2) and work done during the Carnot cycle. It explains that the heat added to the system (Q1) can be equated to the work done when there is no change in internal energy. The work is expressed as the integral of pressure times the differential change in volume over the cycle's path on a PV diagram. The script then discusses how to evaluate these integrals by using the ideal gas law and the fact that the processes occur at constant temperatures, leading to the conclusion that Q1 and Q2 can be calculated as the product of the number of moles, gas constant, temperature, and the natural logarithm of the volume ratio between initial and final states.
π‘οΈ Defining a New State Variable Related to Heat Transfer
The speaker hypothesizes a new state variable, S, which changes proportionally to the heat added divided by the temperature at which it was added. The paragraph explores the validity of S as a state variable by examining its behavior over the Carnot cycle. It concludes that the change in S (delta S) over a complete cycle is zero, making it a legitimate state variable. The calculation involves summing the heat transfer divided by temperature for each isothermal process in the cycle and simplifies to the natural logarithm of the volume ratio, which has been proven to be consistent across all processes in the cycle, thus validating S.
π The Implications of the State Variable S in Cyclic Processes
The final paragraph reflects on the implications of the newly defined state variable S, which remains unchanged after a complete cycle, indicating its legitimacy as a state variable. It emphasizes that although the exact physical meaning of S is not yet clear, its mathematical behavior is consistent with the properties of a state variable. The speaker suggests that further exploration in future videos will be needed to develop a deeper understanding of S at a more intuitive level.
Mindmap
Keywords
π‘State Variable
π‘Carnot Cycle
π‘Heat Content
π‘Adiabatic Process
π‘Isothermal Process
π‘Internal Energy
π‘Work
π‘Enthalpy
π‘Entropy
π‘Ideal Gas Law
π‘Natural Logarithm
Highlights
The state variable U (internal energy) should remain constant at a given point in the PV diagram, regardless of the path taken to return to that point.
Heat cannot be used as a state variable because it depends on the path taken in the PV diagram.
Introducing a hypothetical 'heat content' variable demonstrates why heat is not a state variable due to its dependence on the process path.
In a Carnot cycle, the net heat added to the system equals the net work done by the system, as the internal energy change is zero.
A legitimate state variable is independent of the process path and depends only on the state of the system.
Defining a new state variable S as the change in heat added to the system divided by the temperature at which it was added.
To validate S as a state variable, the change in S (ΞS) around the Carnot cycle should be zero.
During the Carnot cycle, the calculation of ΞS involves Q1/T1 and Q2/T2, where Q1 is the heat added and Q2 is the heat removed.
Q1 can be calculated using the area under the PV curve during the isothermal expansion from A to B.
Q2 can be calculated similarly during the isothermal compression from C to D.
By integrating pressure as a function of volume for isothermal processes, Q1 and Q2 are determined using the ideal gas law.
The final expression for ΞS around the Carnot cycle involves the natural logarithms of volume ratios.
The natural log relationship shows that the volumes at different stages of the cycle are proportional, leading to the conclusion that ΞS is zero.
Proving that ΞS is zero confirms that S is a legitimate state variable.
S represents a state variable related to heat, though its micro-level interpretation requires further exploration.
Transcripts
Browse More Related Video
Thermodynamic entropy definition clarification | Physics | Khan Academy
Enthalpy | Thermodynamics | Chemistry | Khan Academy
23. The Second Law of Thermodynamics and Carnot's Engine
Heat of formation | Thermodynamics | Chemistry | Khan Academy
Statistical Mechanics Lecture 3
Thermodynamic Processes (Animation)
5.0 / 5 (0 votes)
Thanks for rating: