8 | FRQ (Long) | Practice Sessions | AP Chemistry
TLDRIn this AP Daily Practice session, Kristen Cacciatore guides students through the process of determining the iodide (I-) content in tablets containing potassium iodide (KI) and a water-soluble sugar. The video covers the chemical reaction between KI and lead nitrate (Pb(NO3)2), resulting in the formation of a yellow precipitate, lead iodide (PbI2). The session explains the importance of using net ionic equations to represent the reaction, the significance of drying and weighing the precipitate to ensure all water is removed, and how to calculate the mass percent of iodide in the tablet. Additionally, it addresses the impact of varying water volumes on the experiment and the potential use of silver nitrate (AgNO3) as an alternative to lead nitrate for precipitating iodide. The video concludes with a discussion on the limitations of measuring the mass of AgI to three significant figures with a balance that measures to the nearest 0.01 grams. Throughout, Kristen provides tips for further study and resources for AP exam review.
Takeaways
- ๐ **Session Focus**: The session is dedicated to practicing long free response questions for the AP exam.
- ๐ **Resource Availability**: A PDF with practice questions is available for download via a link in the video or description.
- ๐งช **Chemical Reaction**: The net ionic equation for the reaction between KI and Pb(NO3)2 is Pb^2+ + 2I^- โ PbI2(s), representing the formation of a yellow precipitate.
- โ๏ธ **Net Ionic Equation**: It is used to simplify the reaction by showing only the reacting species, omitting the spectator ions like K^+ and NO3^-.
- ๐ **Drying and Weighing**: The process of drying and weighing the filter paper with the precipitate multiple times ensures that all water is removed, providing an accurate mass of the precipitate.
- ๐ **Excess Reagent**: The use of excess Pb(NO3)2 ensures that all I^- reacts, and the concentration of NO3^- is higher than K^+ in the solution.
- ๐งฎ **Calculating Moles**: The number of moles of precipitate is calculated by subtracting the mass of the filter paper from the total mass and then converting to moles using the molar mass of PbI2.
- ๐ **Mass Percent Calculation**: The mass percent of I^- in the tablet is determined after calculating the moles of PbI2, converting to moles and mass of I^-, and using the mass of the tablet.
- โณ **Water Volume Impact**: Changing the volume of water used to dissolve the tablet does not affect the mass percent of I^- determined, as the limiting reactant and product formation are not influenced by the water volume.
- ๐ **Substitution of Reagents**: Using AgNO3 instead of Pb(NO3)2 will result in the precipitation of I^- as AgI due to the low solubility of AgI, indicated by its Ksp value.
- ๐ **Precision Limitation**: With a balance that measures to the nearest 0.01 grams, it's not possible to determine the mass of AgI produced to three significant figures if the mass of the precipitate is less than 1 gram.
- ๐ **Additional Resources**: For further review, the video suggests specific topics on AP Daily, covering net ionic equations, stoichiometry, solubility equilibria, and significant figures.
Q & A
What is the task given to the student in the video?
-The student is tasked with determining the iodide (I-) content of tablets that contain potassium iodide (KI) and an inert water-soluble sugar as a filler.
What is the significance of using distilled water to dissolve the tablet?
-Distilled water is used to dissolve the tablet because it is free from impurities and dissolved substances that could interfere with the chemical reaction or the subsequent analysis.
Why is an excess of 0.20 molar Pb(NO3)2(aq) added to the solution?
-An excess of 0.20 molar Pb(NO3)2(aq) is added to ensure that all the iodide ions (I-) react to form a yellow precipitate of lead(II) iodide (PbI2), leaving essentially no I- ions in the solution.
What is the balanced net ionic equation for the reaction that forms the precipitate?
-The balanced net ionic equation for the reaction is Pb2+(aq) + 2I-(aq) โ PbI2(s), representing the formation of the solid precipitate from lead and iodide ions.
Why is it important to dry and weigh the filter paper with the precipitate multiple times?
-Drying and weighing the filter paper with the precipitate multiple times is crucial to ensure that all the water has been evaporated, allowing for an accurate measurement of just the precipitate's mass.
In the filtrate solution, is the concentration of K+ greater than, less than, or equal to NO3-?
-The concentration of K+ is less than that of NO3- because Pb(NO3)2 is added in excess, ensuring a higher concentration of nitrate ions in the solution.
How is the number of moles of precipitate produced in the experiment calculated?
-The number of moles of precipitate is calculated by first determining the mass of just the precipitate (subtracting the mass of the filter paper), and then dividing this mass by the molar mass of PbI2.
What is the mass percent of I- in the tablet?
-The mass percent of I- in the tablet is calculated by converting moles of PbI2 into moles of I-, then into mass of I-, and finally dividing by the mass of the tablet and multiplying by 100 to get a percentage.
If a tablet is dissolved in 55.0 mL of water instead of 50.0 mL, will the experimentally determined mass percent of I- be affected?
-No, the experimentally determined mass percent of I- will not be affected because the amount of water used only serves as a medium for the reaction and is later removed by filtration and drying, leaving the same mass of precipitate.
Will the substitution of AgNO3 for Pb(NO3)2 result in the precipitation of I- from the solution, given the Ksp value for AgI?
-Yes, the substitution of AgNO3 for Pb(NO3)2 will result in the precipitation of I- from the solution because AgI has a very low Ksp value (8.5 ร 10^-17), indicating it is insoluble and will precipitate under these conditions.
Can the student determine the mass of AgI produced to three significant figures with a balance that measures to the nearest 0.01 grams?
-No, the student cannot determine the mass of AgI produced to three significant figures with such a balance because the mass of the precipitate is less than 1 gram, and the balance's precision limits the measurement to two significant figures.
What are some topics on AP Daily that could help a student struggling with the concepts presented in the video?
-Topics that could help include net ionic equations (topic 4.2), stoichiometry (topic 4.5), solubility equilibria and Ksp (topic 7.11), and gravimetric analysis and significant figures, which should be part of the student's lab notebook.
Outlines
๐ Session 8: Long Free Response Questions Overview
Kristen Cacciatore introduces session 8 of AP Daily Practice, focusing on long free response questions, which are a part of the AP exam. She provides a link for viewers to download a PDF of the questions to practice independently. The session involves a scenario where a student is tasked with determining the iodide (I-) content in tablets containing potassium iodide (KI) and a soluble sugar filler. The process involves dissolving a tablet in water, adding an excess of lead nitrate (Pb(NO3)2) to form a yellow precipitate, which is then filtered, washed, and dried. The discussion covers writing a balanced net ionic equation for the reaction, explaining why a net ionic equation is used, the purpose of drying and weighing the precipitate, and the concentration comparison of potassium (K+) and nitrate (NO3-) ions in the solution.
๐งช Calculating Moles and Mass Percent of Precipitate
The video continues with a step-by-step calculation to determine the number of moles of the precipitate produced in the experiment. It involves subtracting the mass of the filter paper from the total mass to find the mass of the precipitate alone. The molar mass of lead(II) iodide (PbI2) is calculated using the molar masses of lead and iodine. With the mass of the precipitate, the number of moles of PbI2 is determined. The calculation proceeds to find the mass percent of iodide in the tablet by converting moles of PbI2 into moles of iodide (I-), then into mass of I-, and finally performing a percentage calculation using the mass of the tablet. The video also addresses a hypothetical scenario where a different volume of water is used and predicts the effect on the experimentally determined mass percent of I-. It concludes with a discussion on whether AgNO3 can be substituted for Pb(NO3)2 to precipitate I- from a solution, considering the solubility product constant (Ksp) of silver iodide (AgI).
๐ Precision in Measurement and Additional Study Tips
The final paragraph addresses the question of whether a student can determine the mass of silver iodide (AgI) produced to three significant figures with a balance that measures to the nearest 0.01 grams. It is concluded that with the mass of the precipitate being less than 1 gram and the balance's precision limit, only two significant figures can be accurately determined. The video concludes with study tips for reviewing the content covered, including topics on net ionic equations, stoichiometry, solubility equilibria, and Ksp. It also mentions additional AP Daily practice sessions and exam reviews from the past two years as resources for further study.
Mindmap
Keywords
๐กNet Ionic Equation
๐กStoichiometry
๐กGravimetric Analysis
๐กSolubility Product Constant (Ksp)
๐กSignificant Figures
๐กExcess Reagent
๐กPrecipitate
๐กMolar Mass
๐กMass Percent
๐กSpectator Ions
๐กFiltering and Drying
Highlights
Session 8 focuses on preparing students for long free response questions on the AP exam.
A data table presents a scenario where a student must determine the iodide (I-) content of tablets containing KI and a water-soluble sugar filler.
The tablet is dissolved in 50.0 mL of distilled water and reacted with an excess of 0.20 M Pb(NO3)2 to form a yellow precipitate of PbI2.
The balanced net ionic equation for the reaction is written as Pb2+ + 2I- โ PbI2(s).
Net ionic equations are used to show only the reacting species and omit the spectator ions.
The purpose of drying and weighing the filter paper with the precipitate multiple times is to ensure all water has been removed, leaving just the mass of the precipitate.
In the filtrate solution, the concentration of K+ is less than NO3- because Pb(NO3)2 was added in excess.
The number of moles of precipitate produced is calculated by first finding the mass of just the precipitate, then using the molar mass of PbI2.
The mass percent of I- in the tablet is determined by converting moles of PbI2 to moles of I-, then to mass of I-, and finally calculating the percent using the mass of the tablet.
In a different trial where the tablet is dissolved in 55.0 mL of water instead of 50.0 mL, the mass percent of I- is predicted to be equal to the previous calculation since the amount of water does not affect the reaction.
If AgNO3 is substituted for Pb(NO3)2, I- will precipitate as AgI due to the very low Ksp value of 8.5 x 10^-17, indicating AgI is insoluble.
With only one KI tablet and a balance measuring to the nearest 0.01 grams, the student will not be able to determine the mass of AgI produced to three significant figures.
The video provides tips for reviewing the content, suggesting specific topics on AP Daily to focus on based on different parts of the problem.
Additional AP Daily practice sessions and AP exam reviews from the last two years are available as resources.
The importance of gravimetric analysis and significant figures in solving the problem is emphasized.
The video concludes by encouraging students to utilize the provided resources and thanking them for watching.
Transcripts
Browse More Related Video
Chemical Reactions (1 of 11) Double Replacement Reactions, An Explanation
How to do Gravimetric Analysis in Chemistry (with calculations and examples!)
Solution Stoichiometry - Finding Molarity, Mass & Volume
6 | FRQ (Long) | Practice Sessions | AP Chemistry
4 | MCQ | Practice Sessions | AP Chemistry
2 | FRQ (Short) | Practice Sessions | AP Chemistry
5.0 / 5 (0 votes)
Thanks for rating: